Answer:
The required expression is
Step-by-step explanation:
The difference of squares formula is given by
We have been given that one factor is 2x+5. Hence, a = 2x, b = 5
It means that other factor must be (a-b) = (2x-5)
Hence, in order to find the expression, we can multiply the factors.
Using the difference of squares formula
Therefore, the required expression is
A. 10a^4b^3
B. 3a^4b^4
C. 10a^4b^4
D. 3a^4b^3
Answer:
the answer is C
Step-by-step explanation:
19.65 + 2.35 is exactly 22, not including tax
Answer:
A and C
Step-by-step explanation:
A. 15% off $25
15% = 0.15
0.15 x 25 = 3.75
25 - 3.75 = 21.25
22 or under? Yes
B. 30% off $32
30% = 0.30
0.30 x 32 = 9.60
32 - 9.60 = 22.40
22 or under? No
C. $19.65 plus a 2.35 shipping fee
19.65 + 2.35 = 22
22 or under? Yes
D. $20.45 plus a $1.60 shipping fee
20.45 + 1.60 = 22.05
22 or under? No
Even though this is late, the other answer did not mention A being the answer as well so I hope this helped!
16, 11, 6, 1
Answer:
Subtracting the number 5 every time.
The all other 3 factors of the equation x⁴ + 2x³ − 7x² − 8x + 12 will b e(x + 2),(x - 1) and (x + 3).
Roots of an equation are the solution of that equation since an equation consists of hidden values of the variable to determine them by different processes and then the resultant is called roots.
For example root of x -4 = 0 is x = 4 so 4 will be the only root of this linear equation.
Given the equation,
x⁴ + 2x³ − 7x² − 8x + 12
If (x - 2) is a factor of the equation then it should be divisible by it.
So,
(x⁴ + 2x³ − 7x² − 8x + 12) / (x - 2) = (x³ + 4x² + x - 6)
Now divide by (x - 1) of (x³ + 4x² + x - 6)
(x³ + 4x² + x - 6) / (x - 1) = x² + 5x + 6
So,
⇒ (x - 2)(x - 1)(x² + 5x + 6)
⇒ (x - 2)(x - 1)( x² + 2x + 3x + 6)
⇒ (x - 2)(x - 1)[ x(x + 2) + 3(x + 2) ]
⇒ (x - 2)(x - 1)(x + 2)(x + 3)
Hence "The all other 3 factors of the equation x⁴ + 2x³ − 7x² − 8x + 12 will b e(x + 2),(x - 1) and (x + 3)".
To learn more about the roots of an equation,
#SPJ2
Answer:
Step-by-step explanation:
The given equation is:
Now, (x-2) is a factor of the given equation, therefore
Therefore, the other factors are (x-1), (x+2) and (x+3).