the area of the rectangle is 85 cm. express the perimeter of the rectangle is function of the width x.

Answers

Answer 1
Answer: the \ width : \ x \n the \ length : \ y \n The area : \ A=85 \n \nA=xy \n \n85=xy\n \ny= (85)/(x)


Answer 2
Answer: f(x)=85-2(y)  I think it is so .

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In order to go to college, Hank goes from working full-time making $28,000 per year to working part-time at half the salary for two years. The cost of his education will be $5,000. If Hank makes $33,000 per year after getting his degree, approximately how many years will it take him to recover his investment?

Answers

The correct answer is:

6.6 years.

Explanation:

Since he goes from making $28,000 per year to $14,000 per year, he will lose $14,000 each year that he works part-time. He intends to do this for 2 years; this will be a loss of $14000(2) = $28,000.

We will add the cost of his degree to this: 28,000+5,000 = $33,000.

He will be making $33,000 per year when he graduates. This is 33000-28000 = 5000 more per year than he made before.

To find out how many years it will take him to recover his investment, we divide the amount he loses, 33,000, by the extra amount he will make per year, 5000:

33000/5000 = 6.6

Answer: C 6.6 years

Step-by-step explanation: edge 2022

How do you solve x^2 plus 16x plus 63=0?

Answers

x^2+ 16x + 63=0 \n \na=1, \ b=16 , \ c=63 \n \n \Delta =b^2-4ac =16^2 -4\cdot1\cdot 63 = 256 -252 = 4 \n \nx_(1)=(-b-\Delta )/(2a)=(-16-√(4))/(2 )=(-16-2)/(2)=-(-18)/(2)=-9 \n \nx_(2)=(-b+\Delta )/(2a)=(-16+√(4))/(2 )=(-16+2)/(2)=-(-14)/(2)=-7 \n \n \nAnswer : \ x= -7 \ \ or \ \ x= -9

Need help really bad please

Answers

Problem 1

Answer: Choice B) angle1 = 26, angle2 = 64

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Explanation:

Complementary angles add to 90

(angle1)+(angle2) = 90

(5x+6)+(68-x) = 90

4x+74 = 90

4x = 90-74

4x = 16

x = 16/4

x = 4

So,

angle1 = 5x+6 = 5(4)+6 = 26

angle2 = 68-x = 68-4 = 64

Note how

angle1+angle2 = 26+64 = 90

to help check our answer

==========================================

Problem 2

Answer: Choice D) BC, AC, AB

----------

Explanation:

The shortest side of a triangle is always opposite the smallest angle.

The longest side of a triangle is always opposite the largest angle.

Based on those two facts, we can say the shortest side is BC (since angle A = 53 is the smallest angle) and the longest side is AB (since angle C = 70 is the largest)

The order from smallest to largest is

BC, AC, AB

==========================================

Problem 3

Answer: Choice D) B < C < A

----------

Explanation:

Use the reverse of the idea from problem 2. We know that AC is the smallest side which must mean that angle B is the smallest angle. Since BC is the largest side, angle A must be the largest angle.

The order of the angles is B < C < A

==========================================

Problem 4

Answer: Choice A) angle 5 = 50, angle 8 = 130

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Explanation:

The same side exterior angles must be supplementary to have parallel lines.

==========================================

Problem 5

Answer: Choice A) angle G is the smallest

----------

Explanation:

Use the same idea as problem 2. The smallest angle is opposite the smallest side. The smallest side is 48, so angle G being opposite of that side, is the smallest angle.

Angle O would be the largest as it is opposite the largest side DG = 70

A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind. Find the speed of the wind if the​ pilot's speed in still air is 315 miles per hour.

Answers

Given:

A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind.

Pilot's speed in still air is 315 miles per hour.

To find:

The speed of the wind.

Solution:

Let the speed of wind be x miles per hour.

Speed with wind = 315+x miles per hour

Speed against wind = 315-x miles per hour

We know that,

Time=(Distance)/(Speed)

According to the question,

(450)/(315+x)=(360)/(315-x)

Divide both sides by 90.

(5)/(315+x)=(4)/(315-x)

By cross multiplication, we get

5(315-x)=4(315+x)

5(315)-5x=4(315)+4x

5(315)-4(315)=4x+5x

(5-4)315=9x

Divide both sides by 9.

((1)315)/(9)=x

35=x

Therefore, the speed of wind is 35 miles per hour.

Final answer:

The speed of the wind is calculated using uniform motion equations for when the pilot is traveling with the wind and against the wind is w = 45 mph,

Explanation:

This is a problem that involves uniform motion, often taught in high school algebra. Let's denote the speed of the wind as w. Since the time it takes for the pilot to travel 450 miles with the wind is the same as the time it takes for them to travel 360 miles against the wind, we can establish two equations which both equal to time (distance/speed).

With the wind: 450/(315+w) = time

Against the wind: 360/(315-w) = time

As both sides equal to 'time', we can equate them together:

450/(315+w) = 360/(315-w)

Solving this equation, we find that w = 45 mph, which is the speed of the wind.

Learn more about Speed of the wind here:

brainly.com/question/34347046

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A car travels 32 km due north andthen 46 km in a direction 40° west of
north. Find the magnitude of the
car's resultant vector.

Answers

Answer:

73.2km

Step-by-step explanation:

first you have to decompose 46 km into y and x components.

x=sin40°*46km

x=0.64*46km

x=29.44km

y=cos40°*46km

y=0.76*46km

y=34.96

now you add the y components together

32+34.96=66.98

finally use Pythagorean thereom to find the resultant vector.

a*a+ b*b=c*c

66.98*66.98+29.44*29.44=c*c

c*c= 4486.3+866.7

c=√5353

c=73.2 km this is the approximate value

Let A={2,3} and B= {7,8}.write the power set of AxB.

Answers

A=\{2;\ 3\};\ B=\{7;\ 8\}\n\nA* B=\{(2;7);\ (2;8);\ (3;7);\ (3;8)\}\n\nPower\ set\ of\ A* B\ is\ the\ set\ of\ all\ subsets\ of\ A* B\n\n\mathbb{P}(A* B)=\{\O;\ \{(2;7)\};\ \{(2;8)\};\ \{3;7)\};\ \{(3;8)\}\n\{(2;7);\ (2;8)\};\ \{(2;7);\ (3;7)\};\ \{(2;7);\ (3;8)\};\n\{(2;8);\ (3;7)\};\ \{(2;8);\ (3;8)\};\ \{(3;7);\ (3;8)\}\n\{(2;7);\ (2;8);\ (3;7)\};\ \{(2;7);\ (2;8);\ (3;8)\};\n\{(2;7);\ (3;7);\ (3;8)\};\ \{(2;8);\ (3;7);\ (3;8)\}\n\{(2;7);\ (2;8);\ (3;7);\ (3;8)\}\}