Answer:
6,1,3
Step-by-step explanation:
The spilled sauce is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2.
Part A: Find the area of the circle of spilled sauce as a function of time, or A[r(t)]. Show your work. (6 points)
Part B: How large is the area of spilled sauce after 5 minutes? You may use 3.14 to approximate π in this problem. (4 points)
Answer:
A: π(2t)^2 = 4πt^2
B: 4π5^2 5^2= 25x4= 100x3.14=314.
answer to B: 314(.159)
Step-by-step explanation:
b. Write a two-step ordered-pair rule, for the transformation sequence.
Answer:
a) Δ ABC is rotated around the origin by angle 180° and then translated 1
unite to the right and 3 units up
b) R (O , 180°) and T (x + 1 , y + 3)
Step-by-step explanation:
* Lets revise some transformation
- If point (x , y) rotated about the origin by angle 180° then its image
is (-x , -y)
- If the point (x , y) translated horizontally to the right by h units
then its image is (x + h , y)
- If the point (x , y) translated horizontally to the left by h units
then its image is (x - h , y)
- If the point (x , y) translated vertically up by k units
then its image is = (x , y + k)
- If the point (x , y) translated vertically down by k units
then its image is (x , y - k)
* Lets solve the problem
∵ Δ ABC change its place from 2nd quadrant to the 4th quadrant
and reverse its direction Point A up and its image A" down
∵ No change in its size
∴ Triangle ABC rotates 180° clockwise around the origin
# Remember : There is no difference between rotating 180° clockwise
or anti-clockwise around the origin
∵ The vertices of Δ ABC are:
# A = (-3 , 5)
# B = (-3 , 2)
# C = (-1 , 2)
∵ If point (x , y) rotated about the origin by angle 180° then its image
is (-x , -y)
∴ A'' = (3 , -5)
∴ B'' = (3 , -2)
∴ C'' = (1 , -2)
∴ Triangle ABC rotates 180° around the origin to form ΔA"B"C"
∵ The vertices of Δ A'B'C are:
# A' = (4 , -2)
# B' = (4 , 1)
# C' = (2 , 1)
- By comparing the x-coordinates and y-coordinates of points of
Δ A''B''C'' and Δ A'B'C' we will find that every x-coordinate add by 1
and every y-coordinate add by 3
∵ 4 - 3 = 1 and 2 - 1 = 1 ⇒ x- coordinates
∵ -2 - (-5) = -2 + 5 = 3 and 1 - (-2) = 1 + 2 = 3 ⇒ y-coordinates
∴ ΔA''B''C'' translates to the right 1 unite and up 3 units to form
Δ A'B'C'
a) Δ ABC is rotated around the origin by angle 180° and then
translated 1 unite to the right and 3 units up
b) R (O , 180°) and T (x + 1 , y + 3)
A graph of a function. The function graph goes through point negative 2, negative 3 and point negative 3, 0.
f (x) = x 2 + 2x − 5
f(x) = + 1
f(x) = 0x2 − 9x + 7
Answer:
f (x) = 3/4 x ^2 + 2x − 5
Step-by-step explanation:
Using equations, the two numbers are 27 and 13, with the first number being 14 less than the second number, and their sum is 40.
Let's represent the two numbers as x (the second number) and y (the first number).
According to the given information:
The first number is 14 less than the second number: y = x - 14
When she adds them, she gets 40: x + y = 40
Now, we can use these two equations to find the values of x and y.
Substitute the value of y from the first equation into the second equation:
x + (x - 14) = 40
Now, solve for x:
2x - 14 = 40
2x = 54
x = 27
Now that we have the value of x, we can find y using the first equation:
y = x - 14
y = 27 - 14
y = 13
So, the two numbers are 27 and 13.
Learn more about equations on:
#SPJ3
Answer:
34 and 6 =40
Step-by-step explanation:
40 divided by 2=20 20-14=6 14+20=34
b. 452.16 sq. in.
c. 18.84 sq. in.
d. 113.04 sq. in.
we know that
Area of the circle is equal to
where
r is the radius
in this problem
therefore
the answer is the option
d. 113.04 sq. in.
The area of the Frisbee is about 113 in.² ( Option D )
The basic formula that need to be recalled is:
Circular Area = π x R²
Circle Circumference = 2 x π x R
where:
R = radius of circle
The area of sector:
The length of arc:
Let us now tackle the problem!
Given:
Diameter of Frisbee = d = 12 in
Unknown:
Area of Frisbee = A = ?
Solution:
Area of the Frisbee could be calculated using the area of circle as follows:
The closest option available will be option D. 113 in.²
Grade: College
Subject: Mathematics
Chapter: Trigonometry
Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse, Circle , Arc , Sector , Area, Inches , Frisbee , Diameter , Radius , Trigonometry ,