A geostationary orbit, also known as a geosynchronous equatorial orbit, is a specific type of circular orbit around the Earth. In this orbit, a satellite's orbital period matches the Earth's rotation period, which is approximately 24 hours. This causes the satellite to appear stationary relative to a fixed point on the Earth's surface, which is why it's commonly used for communication, weather, and broadcasting satellites.
To achieve this, the satellite needs to be at a specific height above the Earth's surface. The altitude at which a satellite will have a period of one day (24 hours) is called the geostationary altitude or the geostationary orbit height.
The calculation to determine this altitude involves using the formula for the orbital period of a satellite:
Where:
- \( T \) is the orbital period (24 hours in this case)
- \( G \) is the gravitational constant
- \( M \) is the mass of the Earth
- \( r \) is the radius of the satellite's orbit (distance from the center of the Earth to the satellite)
Solving for \( r \) with the known values of \( T \), \( G \), and \( M \), you'll find that the satellite needs to be approximately 35,786 kilometers (22,236 miles) above the Earth's surface to have an orbital period of one day.
This altitude allows the satellite to complete one orbit around the Earth in the same amount of time it takes for the Earth to complete one rotation on its axis, effectively staying in the same position relative to a specific point on the Earth's equator.
Correct answer choice is:
C. The filings will be clustered more densely where the field is weakest.
Explanation:
The closer mutually the field lines will be the more powerful the field would be present. The field is really powerful in the axis of the magnet, though as they are frequently accommodated in the magnet itself, the field is quite weak in the air close to the axis. As the field lines make rings, they have to penetrate in one spot and drop at different, the two poles must be extremely close mutually indeed in the air, and the field is consequently stronger. These points are the North and the south poles.
A) 10 Ω
B) 15 Ω
C) 20 Ω
D) 55 Ω
Answer:
Resistor R₃ = 10 Ω
Explanation:
It is given that,
Current flowing in the circuit, I = 2 A
Resistors R₁ = 2 Ω
Resistor R₂ = 3 Ω
Voltage, V = 30 V
We have to find the value of R₃. All three resistors are connected in series. In series combination, the current flowing through the all resistors is same. Firstly, calculating equivalent resistance of three resistors as :
..............(1)
Using Ohm's law :
On solving above equation :
Hence, the correct option is (A) " 10 Ω "
The value of R3 is A) 10 Ω
Ohm's
Coulomb's
Gilbert's
Coulombs is the correct answer.