Subtract of 11 from 20: 20 - 11
The sum of 4 and 9: 4 + 9
Subtract of 11 from 20, then add the sum of 4 and 9:
(20 - 11) + (4 + 9) = 9 + 13 = 22
If gold coin weigh 20 grams. If the coin contains gold,copper and tin and in the ratio 4:3:1 then 10gm of gold is present in coin.
A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.
Given,
A gold coin weigh 20 grams
the coin contains gold, copper and tin and in the ratio 4:3:1
We need to find the amount of gold in the coin.
Now let us add the ratio.
4x+3x+x=20
8x=20
Divide both sides by 8.
x=2.5
The amount of gold in coin is 4x.
4(2.5)=10 gm
Hence, 10 gm of gold is present in 20 grams of coin.
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Answer:
See below
Step-by-step explanation:
2x+4 / x^2-x-6
= 2(x+2)/(x-3)(x+2)
= 2/(x-3)
So the 2 expressions are equivalent
The values of x which make the expressions undefined are those values which make the denominators 0
For 2x+4/ x^2-x-6 they are X=3 and x= -2.
For 2/x-3 they are x =3.
9-3x2+9x8-10/2=
Answer:
0.87
Step-by-step explanation:
I got it right UwU