Notebooks cost $1.20 each. This weekend they will be $.80 What percentage is the sale?

Answers

Answer 1
Answer: In the question it is already given that the actual cost of each notebook is $1.20. For the weekend, the notebooks would sold at a discounted rate of $0.80
he
The amount of discount during the weekend = (1.20 - 0.80) dollars
                                                                       = 0.40 dollars
So the amount of discount given during the weekend is $0.40
Now we need to find the percentage of discount given during the weekend.
Then
Percentage of discount during the weekend = (0.40/1.20) * 100
                                                                       = 0.33 * 100
                                                                       = 33
Then the percentage of discount given is 33%.

Answer 2
Answer: The sale is 33% off notebooks. This can be found by first subtracting .8 from 1.2

1.2-.8=.4    Now divide .4 by 1.2 to get your answer.

(.4)/(1.2)=.33

.33=33%

You can also solve this mentally because if you know your basic multiplication tables, 3*4=12 and so (2)/(3) of 12 would equal 8.

Does you understand it now?

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Hayden graphed the following linear function on an (x,y) coordinat plane. g(x) = 3x -4.5 What is the y-intercept of the graph of this function? Write the numerical value.​

Answers

-4.5 if you were to graph the linear function.

Which is another way to check the sum of 52+23+10+78

Answers

well first off those numbers add up to 163.

A way to check this is to add 52 with 23 which is 75 then add 78 by 10 which is 88 now add 75 with 88 which is 163

PLSSSSSSSSSSS HEEEEEELP????The mean of a set of normally distributed data is 600 with a standard deviation of 20. What percent of the data is between 580 and 620?

Answers

Answer:

The percentage of the data between 580 and 620 is 68.26 %

Step-by-step explanation:

Given,

Mean, \mu = 600,

Standard deviation, \sigma = 20,

Using the equation,

z-score=(x-\mu)/(\sigma)

Z-score for the data 580 = (580-600)/(20)

=(-20)/(20)

=-1

While, the z-score for the data 620 = (620-600)/(20)

=(20)/(20)

=1

Using normal distribution table,

P(580 < z) = 0.1587

Also, P(620 > z) = 0.8413

Hence, the percent of the data is between 580 and 620 = P(620 > z)  - P(580 < z)

= 0.8413  - 0.1587

= 0.6826

= 68.26 %

z = (X-Mean)/SD 
z1 = (580-600)/20 = - 1 
z2 = (620-600)/20 = + 1 
According to the Empirical Rule 68-95-99.7 
Mean +/- 1*SD covers 68% of the values 
Therefore, required percent is 68%
hopes this help :) :D :)

PLEASE HELP DUE TODAY

Answers

Answer:

Five plus the difference of seventeen and eight

Answer: B

Step-by-step explanation: You would add 5 to the sum of 17-8.

A Gallup survey showed that in March 2011, 8 of every 25 employers in the United States were adding more workers to their workforce, 9 of 50 were reducing their workforce, and 1 of 2 were keeping it the same. If there were 1250 employers in one metropolitan area, and those who were hiring planned to hire an average of 7 new employees, how many new jobs were about to become available?

Answers

Final answer:

By applying the provided ratio of hiring employers to the total number of employers, and then multiplying by the average number of new hires per employer, we can conclude that an estimated 2800 new jobs were about to become available in this metropolitan area.

Explanation:

To solve this problem, we must note that 8 in 25 employers were planning to add more employees. This is a ratio of 8/25. With a total of 1250 employers in the area, we can calculate the number of employers that are hiring by multiplying this ratio by the total number of employers: (8/25)*1250 = 400 employers. Each of these employers was set to hire an average of 7 new employees, so we multiply the number of employers hiring by the average number of new hires: 7 new employees * 400 employers = 2800 new jobs. Thus, 2800 new jobs were about to become available in this area.

Learn more about Ratio Calculation here:

brainly.com/question/31549749

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When registering their cars, owners must identify the color that covers the largest portion of the vehicle. In one region, the probability that car was mainly white was 0.24, the probability that it was mainly silver was 0.22, and the probability that it was mainly black was 0.19. In this region, are the events "silver" and "black" mutually exclusive:? Choose 1 answer A) Yes
B) No
Find the probability that a randomly selected car from this region is mainly silver OR mainly black.
P (silver OR black)=

Answers

Answer:

A) Yes

Step-by-step explanation:

Yes, the events silver and black are mutually exclusive, meaning they cannot not happen at the same time. While a car can certainly be black and silver, a car cannot be mainly silver AND mainly black at the same time. One color is going to be dominant

P (silver OR black)= P(silver) + P(black)

                              = 0.22 + 0.19

                              = 0.41

Answer:

yes, 0.41

Step-by-step explanation:

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