MATHEMATICS HIGH SCHOOL

Perform the operations, multiply, and simplify.
-a^3b (3a^2 b^5 - ab^4 - 7a ^2 b)

Answers

Answer 1
Answer: -a^3b (3a^2 b^5 - ab^4 - 7a ^2 b)=\n -3a^5b^6+a^4b^5+7a^5b^2
Answer 2
Answer: -a^3b (3a^2 b^5 - ab^4 - 7a ^2 b) \n \n =-3a^5b^6-(-a^4b^5)-(-7a^5b^2) \n \n =-3a^5b^6+a^4b^5+7a^5b^2

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Estimate the answer by rounding 863 x 534 to the nearest 100
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What is 6.213 as a mixed number

Answers

6.213 as a mixed number would be 6 and 213/1000.

all you do to convert it to a mixed number is look at how many numbers are after the decimal.

since theres 3 numbers, that means it would be in the thousands place

Explain how you could write 35% as the sum of two benchmark percents or as a multiple of a percent.

Answers

Possible correct answers are:

20%+15%; and 50% of 70%.

Explanation:

Benchmark percents are percents that are commonly used. 20% and 15% are two commonly used percentages; the sum of them would be
20%+15% = 35%.

A multiple of a percent is a percent of a percent. Taking 50% of 70% of a number is the same as multiplying by 0.5(0.7) = 0.35.
Best Answer : you would have to divide 35 with the place value it is in. For example :35% ; 35/100 and then you divide which is 0.35, that is your answer. As a fraction 0.35 is really 7/20.

Write 3x(x+4)(x-1) in standard form.

Answers

The Answer you are looking for is
 
3x^3 + 9x^2 - 12x

A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = -0.06x^2 + 10.1x + 5, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?

Answers

Answer:

The horizontal distance from the starting point when rocket lands is:

168.83 meters.

Step-by-step explanation:

We are given a function that models the height of the rocket when it is 'x' meters away from the starting point.

The function is:

y=-0.06x^2+10.1x+5

Now we are asked to find the horizontal distance from the starting point when the rocket will land.

i.e. we are asked to find 'x' ; when y=0

i.e.

Let y=0

-0.06x^2+1.01x+5=0\n\ni.e.\n\n6x^2-1010x-500=0

on solving the quadratic equation we obtain:

x=-0.49360\ and\ x=(125)/(6)=168.83

As the distance can't be negative.

Hence, the viable solution is:

x=168.83
Hello,

y=-0.06x²+10.1x+5
==>6x²-1010x-500=0
Δ=1010²+4*6*500=1032100=(1015,92...)²
x=(1010-1015.92...)/12 <0 exclude
or x=(1010+1015.92..)/12=168.826935... (m)

Dylan’s essential (fixed) expenses are $900 per month, his essential (flexible) expenses are $400 per month, and his non-essential expenses are $295 per month. His 401-K retirement account has $12,000, and his emergency fund savings account has $3500. Dylan wants an emergency fund of 3 times monthly living expenses. How much more does Dylan need to save to have an adequate emergency fund?a. $1,450
b. $5,200
c. $1,285
d. $8,500

Answers

The Following "Verified" Answer is wrong. On Financial Math the answer is...

C.

$1,285

Answer:

Option C. $1,285 more Dylan need to save.

Step-by-step explanation:

Dylan's essential (fixed) expenses = $900 per month

His essential (flexible) expenses = $400 per month

His non-essential expenses = $295 per month

Total expenses per month = 900 + 400 + 295 = $1595.00

He wants an emergency fund of 3 times monthly living expenses

= $1595 × 3 = $4,785.00

currently, in Dylan's emergency fund account = $3,500

Dylan need to save more = 4,785 - 3,500 = $1,285.00

Dylan need to save $1,285 more to have an adequate emergency fund.

Still confusing to me!!!!

Answers

Answer:

  (a)  2(x -a)

  (b)  4x +2h

Step-by-step explanation:

Fill in the function arguments and simplify.

a.

(f(x)-f(a))/(x-a)=((2x^2-7)-(2a^2-7))/(x-a)\n\n=(2x^2-7-2a^2+7)/(x-a)=(2(x^2-a^2))/(x-a)\n\n=(2(x-a)(x+a))/((x-a))=2(x+a)

__

b.

(f(x+h)-f(x))/(h)=((2(x+h)^2-7)-(2x^2-7))/(h)\n\n=(2x^2+4xh+2h^2-7-2x^2+7)/(h)=(4xh+2h^2)/(h)\n\n=4x+2h
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