What is 32,020.20 rounded to the nearest tenth

Answers

Answer 1

Answer: tenth = 0.1
32, 020.20 ≈ 32, 020. 2
if the number you are trying to round are 1, 2, 3, 4, you have to round it down and if it's 5, 6, 7, 8, 9, you have to round it up
2 < 5
therefore, the answer is 32, 020. 2

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Which of the following equations has infinite solution?A. 1/5x+10 =2(1/10x+20)
B. 1/4x -2= -1/2(4 -1/2x)
C. 1/3x + 12 =5(1/3x +12)
D. 1/2x - 6= - 1/5(30 -10x)
Been stuck on this for a while can someone help

Answers

A) $1/5x + 10 = 2(1/10x+20) =$ no solution

B) $1/4x - 2 = -1/2(4-1/2x) =$ infinite solutions

C) $1/3x + 12 =5(1/3x +12) =$ x = -36

D) $1/2x - 6= - 1/5(30 -10x) =$ x = 0

$\fbox {B)}$ has infinite solutions, which is your answer.

a rectangular patio has a length of 12 1/2 feet and an area of 103 1/8 square feet .what is the width of the patio?

Answers

L=Length of the rectangular patio

A=Area of the rectangular patio

W=Width of the rectangular patio

f=foot

------------------------------------

L=25/2f

A=(103+1/8)f²=(824/8+1/8)f²=825/8f²

-----------------------------

Now, A=L*W=825/8f²

-------------------------------

USE BODMAS

Therefore:

25/2fW=825/8f²

So...

W=(825/8f²)/(25/2f)

=33/4f

You just do the area divided by the length, and you get the width, or area divided by width to get the length for future notice. 103 1/8 divided by 12 1/2 might not be 8 1/4! :D

What's the vertex and how did you get it?

Answers

The

$3x^2 + 24x + 36 = 0 \implies 3(x^2 + 8x) + 36 = 0 \implies \n \n 3\left\{x^2 + {\bf 8}x + \left((\bf 8)/(2) \right)^2 - \left((\bf 8)/(2) \right)^2 \right\} + 36 = 0 \implies \n \n 3\left\{x^2 + {\bf 8}x + 16 - 16 \right\} + 36 = 0 \implies \n 3\Big\{(x+4)^2 - 16 \Big\} + 36 = 0 \implies \n \n 3(x+4)^2 - 16(3) + 36 = 0 \implies 3(x+4)^2 - 12 = 0$

The vertex is (-4, 12) because a(x - b)^2 + c has vertex (b, c) so 3(x+4)^2 - 12 has vetex (-4, 12)

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Answers

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Write a doubles fact that can help me solve 6+5=11

Answers

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