How do I solve for x and state the restriction if (a-c)/(x-a)=m

Answers

Answer 1
Answer: (a-c)/(x-a)=m;\ D:x\neq a\n\nm(x-a)=a-c\n\nmx-ma=a-c\n\nmx=a-c+ma\ \ \ \ /:m\neq0\n\nx=(a-c+ma)/(m)
Answer 2
Answer:

(a - c)/(x - a) = m

(x - a) (a - c)/(x - a) = m ( x - a)

a - c = mx - am

a - c + am = mx

(a)/(m) - (c)/(m) + (am)/(m) = x

(a - c)/(m) + a = x


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What is the probability that a student who bought juice chosen at random purchased grape flavor

Answers

Answer: 0.2

Step-by-step explanation: This answer is correct and the answer that the current person put is wrong, it isn’t even an answer choice.

Answer:

50% chance

Step-by-step explanation:

20 is what percent of 52?

Answers

20 is 38.46% of 52. Hope i helped
If 52 ------> =100% (=1)
Then 20----> x
(Rule of 3)
X=20/52 =38.46%

For a quantity that changes frequently from month to month, the best kind of graph is a pie chart. a. True
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Answers

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What is the total amount that First Consumer Bank will receive after lending Jane $7,000 for three years at an interest rate of 5 percent, compounded annually?

Answers

Given:
principal = 7,000
interest rate = 5% compounded annually
term = 3 years

A = P (1 + r/n)^nt

A = future amount to be received by First Consumer Bank
P = loan principal
r = rate
n = number of times compounded in a year
t = term

A = 7,000 ( 1 + 5%/1)^1x3
A = 7,000 (1.05)³
A = 7,000 (1.157625)
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First Consumer Bank will receive 8,103.375 from Jane after lending 7,000 for 3 years compounded annually at 5%.

Only using positive exponents, what is the simplified form of the expression p^−6 q^7 r/ p^2q−2 ?

Answers

Answer:

2

Step-by-step explanation:

add the p and that p will make 2 so just subtract 2 nd 2

Using the U- Substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to ...I'm not quite sure how to solve using u substitution.

Help please!

Answers

We will use u-substitute:u= √(2x) , (du)/(dx)= (1)/( √(2x) )= (1)/(u)Then for substitution:dx=u du. and integral becomes:\int { (u)/(u+1) } \, du = \int { (u+1-1)/(u+1) } \, du= \int{1} \, du- \int { (1)/(u-1) } \, dx=u-ln(u+1)=√(2x)-ln( √(2x)+1). Now we will change the values of limits: √(16)-ln( √(16)+1)-( √(4)-ln( √(4)+1))=4-ln(5)-2+ln(3)=2+ln(0,6)=2-0.51=1.49