C = Celsius
K = k=Kelvin
C + 273.15 = K
200 + 273.15 = K
473.15 = K
The experiments 'The Iced Tea Debate' and 'The Salty Soup' illustrate different physical changes and energy transfers in the context of the Law of Conservation of Matter and Energy.
In 'The Iced Tea Debate', the independent variable could be the temperature of the tea, the dependent variable could be how quickly the ice melts and the control variable could be the amount of tea used in each trial. The Law of Conservation of Matter and Energy states that matter and energy cannot be created or destroyed in an isolated system. In this case, the ice melting is a physical change, and the energy transferred is thermal energy from the tea to the ice.
In 'The Salty Soup,' the independent variable could be the amount of salt added, the dependent variable could be the taste of the soup, and the control variable could be the type of soup used. The added salt dissolving into the soup is a physical change, and no noticeable energy transfer occurs.
One example of conservation of matter and energy in everyday life is the process of photosynthesis in plants. The plant absorbs sunlight (energy), carbon dioxide, and water, and converts them into glucose and oxygen, thus conserving matter and energy.
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In these demonstrations, matter and energy were conserved, as total mass and energy stayed constant. Significant phase and energy transformations were observed, like the melting of ice and the dissolving of salt. The total mass before and after the transformations remained the same, demonstrating the law of conservation of mass.
Matter and energy can be described as being conserved in a variety of systems because they can neither be created nor destroyed, only transferred between objects or converted from one form to another. In 'The Iced Tea Debate' and 'The Salty Soup' demonstrations,
Variables would include: Independent variable: the substance added (be it ice tea or salt); Dependent variable: physical and chemical changes observed; Control variables: the initial conditions of the system, like temperature and pressure.
When analyzing the results of each of these demonstrations, you should observe energy transfers, in the form of heat in both scenarios.
Moreover, there would be conservation of matter observable in both scenarios. This can be proven by extracting and weighing all substances before and after their reactions, summing up the total mass, which should stay constant.
To answer the questions:
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B. liquid
C. water
D. plasma
Answer: Option (C) is the correct answer.
Explanation:
Solid and liquid are the states of matter. Plasma is also a state of matter where a number of electrons move freely around the nucleus of an atom.
Whereas water is a liquid itself and liquid is a state of matter but water is not a state of matter.
Therefore, we can conclude that water is not a state of matter.
is not a state of matter.
Further Explanation:
Matter:
Anything that acquires space and has mass is termed as matter. It is made up of atoms. These atoms can be bonded so strongly or can be far apart from each other. The states of matter can be classified on the basis of features that are visible or can be felt.
States of matter:
1. Solid
It has a definite shape and volume. These are generally hard and have a regular arrangement of its constituent particles. These can be amorphous or crystalline. The intermolecular forces in the solids are very strong and thus the motion of particles in solid is almost negligible. Rock, wood, sugar, and diamond are examples of solids.
2. Liquid
It has a definite volume but can have the shape of any container in which it is placed. The intermolecular forces in the liquids are weaker than that in solids and thus the motion of particles in liquids is more as compared to solids. These have the property to flow. Water, mercury and bromine are examples of liquids.
3. Gas
It has neither a definite shape nor a definite volume. These are highly compressible and have an irregular or disordered arrangement of its constituent particles. The intermolecular forces in the gases are the weakest and thus the motion of particles in a gas is very high. Oxygen, hydrogen and carbon dioxide are examples of gases.
4. Plasma
It has neither a definite volume nor a definite volume. It is present in ionized gases but its uniqueness differentiates it from gases. Plasma contains free charges that make it conductive. Stars and neon signs are examples of plasma.
So solid, liquid and plasma are the states of matter. But water is an example of liquid and therefore an example of a state of matter. Therefore water is not a state of matter.
Learn more:
1. The subatomic particle with the least mass: brainly.com/question/2224691
2. Bohr’s model of the atom: brainly.com/question/2965079
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Matter in our surroundings
Keywords: state of matter, solid, liquid, water, plasma, matter, bromine, hydrogen, diamond, volume, shape, hard, flow, regular arrangement, constituent particles,
fluorine
chlorine
sulfur
bromine
1s² 2s² 2p⁶ 3s² 3p⁵ is the electron configuration for B)chlorine.
The 4 special types of orbitals (s,p,d, and f) have distinctive shapes, and one orbital can hold a most of twoelectrons. The p, d, and f orbitals have different sublevels, accordingly can keep extraelectrons. As stated, the electronconfiguration of each detail is precise to its position on the periodic table.
In atomic physics and quantumchemistry, the electronconfiguration is the distribution of electrons of an atom or molecule (or different bodily structure) in atomic or molecularorbitals.
Learn more about electron configuration here: brainly.com/question/11316046
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Answer:Neutrons, Electrons, and Protons
Ideal gas law is valid only for ideal gas not for vanderwaal gas. Charles' gas law is used here. Therefore the new volume of the balloon in the hot room is 3.68 L.
Ideal gas equation is the mathematical expression that relates pressure volume and temperature. Vanderwaal gas can behave as ideal gas low pressure and high temperature.
Mathematically the relation between Pressure, volume and temperature can be given as
PV=nRT
where,
P = pressure of gas
V= volume of gas
n =number of moles of gas
T =temperature of gas
R = Gas constant = 0.0821 L.atm/K.mol
Combining Boyle's and Charles' gas law
V₁/T₁ = V₂/T₂
3.50 L ÷298 K = V₂÷313 K
V₂ = 3.68 L
Therefore the new volume of the balloon in the hot room is 3.68 L.
To learn more about ideal gas equation, here:
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yes, according to charles law, this would be equal to 3.68 L