a store owner is arranging clothing on racks. She has 30 sweaters, 45 shirts and 15 pairs of jeans. She wants to put the same number of items on each rack, with only one type of item on each. How many items can she put on a rack?
Answers
1 x 15 and 3 x 5 so the she can put one of each, or she can put 3 of each,
or she can put 5 of each , or she can put 15 of each.
The problem is unclear however because as worded she could put 2 sweaters, 2 shirts and 2 pair of jeans. I think the teacher wants all the jeans used. The number 1,3,5 and 15 will use up all of the jeans.
1 jean on 15 racks
or 3 jeans on 5 racks
or 5 jeans on 3 racks
or 15 jeans on one rack
These are the sort of ambiguous word problems 4th graders are exposed to on a daily basis. As the gentleman mentioned, the teacher expects 15, the largest common factor but 1 on each rack fits as well. It should have read “what’s the maximum number of the same item can he/she place on the racks?”
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Answers
the solutions (1,2)
we subsitute and find that the answer is the first equation
we add them together and get
we negative the first and add
-2x+2x+y+y=5+5
2y=10
y=10
sutaitute
2x-y=-5
2x-10=-5
we can see that there is 1 solution
Answers
80/2 = 40, that's how many litres when it's half full
It will hold 40 litres
SO... you have to half that giving you 40. The answer is 40
2)y=9/5x-5
Find the slope of a line perpendicular to each given line
1)y=-1/2x-2
2)y=-x-1
Answers
Slopes of perpendicular lines are opposite reciprocals, which means when they are multiplied, it equals to -1.
1)
Parallel lines have the same slopes
y=mx+b where m is the slope
so the slope of a parallel line would be 2/3
2)
y=9/5x -5
slope will be 9/5
Next set of questions:
1) y=-1/2x - 2
So that means the slope is 2
2) y=-x-1
Slope is -1, and we need to find the slope for a line perpendicular to it.
So the slope is 1
Answers
Answer:
the answer is 180 feet
Step-by-step explanation:
because it is a square all sides are equal so the distance is between two lines so you only have to add two sides: (90+90=180).
Answers
It depends on what you are trying to find if you are trying to find the unit rate for oz/dollar or dollar/oz it differs. But, for the second option it is $0.14 dollars. For the first it is 7.32 oz per dollar. I assume you are trying to find dollar/oz because it makes more sense.
Answers
Lets set 1 cat's mass as x.
Lets set the other cat's mass as y.
1) x+y=11
2) y=x+1.5
Lets plug eq 2 into eq 1.
x+x+1.5=11
2x+1.5=11
2x=9.5
x=4.75 kg
If one cat weighs 4.75 kg, then the other must weigh 6.25 kg.
cat2=y
x+y=11kg
11kg=11000g
x=y+1500
subsitute
y+1500+y=11000
subtract 1500
2y=9500
divide by 2
y=4750
subsitue
x=4750+1500
x=6250
one cat weighs 6250g and the other weighs 4750g