If the coordinates of point P are (0,8) and the coordinates of point Q are ( 4,2), Which of the following points represents the midpoint of PQ ?a) (0,2), b) (2,4), c) (2,5), d) (4,8), e) (4,10)

Answers

Answer 1
Answer: The coordinates of the midpoint are just the average of the endpoint coordinates ...
x-mid is the average of the end-x's, and y-mid is the average of the end-y's.

P. x = 0, y = 8
Q. x = 4, y = 2

'x' of the midpoint is the average of 0 and 4 = (1/2)(0 + 4) = 2

'y' of the midpoint is the average of 8 and 2 = (1/2)(8 + 2) = 5

The midpoint is (2, 5) .

That's choice-'c'. 
Answer 2
Answer: There is midpoint formula for this problem:[ (x1+x2)/2, (y1+y2)/2 ], so all you need to do is plug in points given  P(x1=0, y1=8) and Q(x2=4, y2=2), which is [ (0+4)/2, (8+2)/2 ]=     [ 2, 5], so the answer is c)

Hope this helps!

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3x^3 +2x^2y + 3xy^2 + 2y^3 =\n \n=x^2(3x+2y) +y^2(3x+2y)=\n \n=(3x+2y)(x^2+y^2)


What is the approximate area of a circle whose radius is 3 m long? (Use 3.14 for pi.)

Answers

Area of a circle (formula) = \pi
                                        =(3)²\pi
                                        =9\pi    (using 3.14 as \pi)
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What is the difference between points a (1,2) and b (9,17)

Answers

Answer:

Step-by-step explanation:

-distance formula: d = √((x_2 - x_1)^2 + (y_2-y_1)^2)

(1,2) is (x_(1) , y_(1)) respectively

(9,17) is x_(2) , y_(2) respectively

-plug in the values to the formula

\sqrt (9-1)^(2) +(17-2)^(2) \n\sqrt 8^(2) +15^2\n\sqrt 64 + 225\n\sqrt 289\n\n17

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Answers

this is the formula!!!!!!?
u mean this???

Factor 26r3s + 52r5 – 39r2s4. What is the resulting expression? 13(2r3s + 4r5 – 3r2s4)
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13r2(26r3s + 52r5 – 39r2s4)

Answers

Answer:

Option 3rd is correct

13r^2(2rs+4r^3-3s^4)

Step-by-step explanation:

GCF (Greatest common factor) is the largest number that divides the two number.

Factor 26r^3s+52r^5-39r^2s^4

Find the GCF of the given expression.

GCF of 26r^3s, 52r^5 and 39r^2s^4 is, 13r^2

then;

13r^2(2rs+4r^3-3s^4)

Therefore, the  resulting expression is, 13r^2(2rs+4r^3-3s^4)

Answer:

The Given Expression is

26r^3s + 52r^5 -39r^2s^4\n13* 2* r* r^2 * s + 13* 2* 2* r^2* r^2* r- 13 * 3* r^2* s * s^3\n\n\text{Taking out common factors}\n\n13r^2(2 rs + 2* 2 r^3 -3 s^4)\n\n13r^2(2 r s+ 4 r^3 - 3 s^4)

Option  <strong>13r^2(2 rs + 4 r^3 - 3 s^4) is correct option.

a baker is using a cake- decorating bag in the shape of a cone. if it's diameter is 4 inches and height is 9 inches , how much frosting can fit in the bag?

Answers

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V = pi 4 x 9 ÷ 3
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