MATHEMATICS HIGH SCHOOL

Use benchmarks to estimate the sum, difference, or product.3. 15/16 1/6
a. 3
b. 1 1/2
c. 2
d. 1

Answers

Answer 1
Answer: my opinion is d/1 okay and i did not understand

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Factor this radical expression. 50a^2-10ab/20a^3b^3

Answers

remembe
(ax)/(bx)=(a/b)(x/x)=(a/b)1
find ones aka common factors and use distributive

top
50a^2-10ab
common facotrs is 10a
undistribute (ab+ac=a(b+c))
10a(5a-b)

bottom
20a^3b^3
see if 10a is also a common factor and undistribute that to cancel and make ones
10a(2a^2b^2)

now we have
(10a(5a-b))/(10a(2a^(2)b^(3))=(10a)/(10a)(5a-b)/(2a^(2)b^(3))
1)split into two fractions 
(50a^(2) )/(20a ^(3) b ^(3) ) - (10ab )/(20a ^(3) b ^(3) )

2) cancel what you can on both sides
(5)/(2ab ^(3) ) - (1)/(2a ^(2)b ^(2) )

3) Make the denominators the same by cross multiplying and then put together as 1 fraction again
(5a-b)/(2a ^(2)b ^(2) )

A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.

Answers

Chair=x

Table=y

Desk=z

\begin{Bmatrix}x+y&=&40\ny+z&=&83\nx+z&=&77\end{matrix}

keep the first row as normal, then in the other ones, we can isolate Y and X

\begin{Bmatrix}x+y&=&40\ny&=&83-z\nx&=&77-z\end{matrix}

now we can replace at first row...

\begin{Bmatrix}(77-z)+(83-z)&=&40\ny&=&83-z\nx&=&77-z\end{matrix}

\begin{Bmatrix}160-2z&=&40\ny&=&83-z\nx&=&77-z\end{matrix}

\begin{Bmatrix}-2z&=&40-160\ny&=&83-z\nx&=&77-z\end{matrix}

\begin{Bmatrix}-2z&=&-120\ny&=&83-z\nx&=&77-z\end{matrix}

\begin{Bmatrix}z&=&60\ny&=&83-z\nx&=&77-z\end{matrix}

now we can replace the Z to discovery the other value

\begin{Bmatrix}z&=&60\ny&=&83-60\nx&=&77-60\end{matrix}

\boxed{\boxed{\boxed{\begin{Bmatrix}Chair&=&17\nTable&=&23\nDesk&=&60\end{matrix}}}}

What is the slope of this table?

Answers

Answer:

Step-by-step explanation: what grade r u in and also help me with my homeork

Round 0.428 to the nearest tenth

Answers

Answer:

.400

Step-by-step explanation:

Simon is making wreaths to sell your 60 bucks 36 roses and 48 silk carnation do you want to percent number of items on each with all the items on a wreath will be the same type how many items can Simon put on each wreath?

Answers

Answer: 12 Wreaths

Explanation:

If he wants to have the same amount of each item on the wreaths, we need to find the factors of each to find the highest amount of wreaths he can make.

60=2×2×3×5=(2×2×3)×5

36=2×2×3×3=(2×2×3)×3

48=2×2×2×2×3=(2×2×3)×2×2

So, 2×2×3 is in each which is equal to 12 so he can make 12 wreaths with the amount and factor on each wreath below:

12 wreaths

5 bows on each

3 silk roses each

4 silk carnations each

Hope this helps! :)

Answer: 12 Wreaths

Explanation:

If he wants to have the same amount of each item on the wreaths, we need to find the factors of each to find the highest amount of wreaths he can make.

60=2×2×3×5=(2×2×3)×5

36=2×2×3×3=(2×2×3)×3

48=2×2×2×2×3=(2×2×3)×2×2

So, 2×2×3 is in each which is equal to 12 so he can make 12 wreaths with the amount and factor on each wreath below:

12 wreaths

5 bows on each

3 silk roses each

4 silk carnations each

Hope this helps! :)

H = vt - 16t^2, solve for v

Answers

The equation h = vt - 16t² is solved for v will be given as v = (h + 16t²) / t.

What is the solution to the equation?

The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.

Making anything easier to accomplish or comprehend, as well as making it lessdifficult, is the definition of simplification.

The equation is given below.

h = vt - 16t²

Simplify the equation for v, then the equation is written as,

h = vt - 16t²

vt = h + 16t²

v = (h + 16t²) / t

The equation h = vt - 16t² is solved for v will be given as v = (h + 16t²) / t.

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ2
H=vt-16t²
vt-16t²=H
vt=16t²+H
v=(16t²+H)/t
v=16(t²/t)+H/t
v=16t+H/t

Answer: the answer would be: v=16t+H/t
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