To test a hypothesis,a scientist designs a (n)------

Answers

Answer 1

Answer: To test a hypothesis, a scientist designs a (n)_experiment(s) _

Answer 2

Answer: Experiment. That is the answer.

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1. How would the world be like if the element named Boron did not exist? 2. How would our lives be if the element Boron did not exist?

Answers

1. The world without boron would be like a "turtle hiding inside it's shell" Almost everything that we need biologically would not be supplied. There would be plant disorder because of lack of boron that is needed for plants growth. And it would be widespread around the world and causes large of scarcity of food production resulting to chain of reaction to other factors that is part of our daily lives. We are not that high-tech as now and the transition of technology would not be as what we would be expecting in the years to come. We may obtain some of it naturally but it would not be enough later on as the population keeps on growing.

2. Life is still life because we still have other resources we need but it would be quite different as Boron plays a vital role since the earth's formation. As it has many uses in the beginning of civilization as we relies on borates for almost everything. Probably, widespread of plant disorder, poor production of food, rampant of sickness may happen, increasing of pestilence that some of the key ingredient of household products relies on it.

A plasma that has particles that never collide frequently enough to exchange kinetic energy and never reach a temperature equal to the surroundings is categorized as a

Answers

Answer: Thermal plasma

Explanation:

Answer:

A on edg

Explanation:

How to do balancing equations

Answers

It's quite hard to explain without an example, but I'll give it a go:

Basically, you have to count the number of an element on one side of the equation, then count it on the other, and the aim of balancing the equation is to get the 2 values to be the same (as mass cannot be created or destroyed).

This involves multiplication of the molecule(s) on either side of the equation in order to balance the whole thing. Note this is not like maths, you dont have to do the same to both sides, but you do have to multiply out entire molecules - you cannot multiply just the H2 in H2O for example.

A reasonably basic example of this balancing is:

Fe + Cl2 = FeCl3

The first thing I notice is that there is an even number of Cl atoms on the left, and an odd number on the right, so the first thing I'll do is multiply the one on the right to get it to an even number, ie by 2.

Fe + Cl2 = 2(FeCl3)

Expanding that gives Fe2Cl6 (although you dont write it like that). So we need to get 6 Cl atoms and 2 Fe atoms by multiplying the left hand molecules by amounts if possible. If you look at that, we can achieve that, by multiplying Cl2 by 3, and Fe by 2.

2Fe + 3Cl2 = 2FeCl3
And there you have your balanced equation, you'll notice that the number of any given element has the same number of atoms on both sides of the equation.

All of the following are true of metals exceptA. can conduct electricity
B. have luster
C. have low melting points ###
D. are malleable

is my answer right?

Answers

Have low melting point

What is the molarity of a solution that contains 14.92 grams magnesium oxide (MgO) in 365ml of solution? a. 1.01 molar solution
b. 1.52 molar solution
c. 11.2 molar solution
d. 87.2 molar solution

Answers

Answer:

a. 1.01 molar solution

Explanation:

Now we have to recall the formula;

n= CV

Where

n= number of moles of magnesium oxide

C= concentration of magnesium oxide solution = ???

V= volume of magnesium oxide solution= 365 ml

But;

n= m/M

Where;

m= given mass of magnesium oxide= 14.2 g

M= molar mass of magnesium oxide= 40.3044 g/mol

Substituting values;

14.2g/40.3044 g/mol = C×365/1000

0.3523= 0.365 C

C= 0.3523/0.365

C= 0.965

C= 1.00 molar (approx)

Answer:

Option A. 1.01 molar solution

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass of MgO = 14.92g

Volume of solution = 365mL

Molarity of solution =.?

Step 2:

Determination of the number of mole present in 14.92g of MgO.

This is illustrated below:

Mass of MgO = 14.92g

Molar mass of MgO = 24.3 + 16 = 40.3g/mol

Number of mole MgO =...?

Mole = Mass /Molar Mass

Number of mole of MgO = 14.92/40.3 = 0.370 mole

Step 3:

Determination of the molarity of the solution.

This can be obtained as follow:

Mole of MgO = 0.370 mole

Volume = 365mL = 365/1000 = 0.365L

Molarity =..?

Molarity = mole /Volume

Molarity = 0.370/0.365

Molarity = 1.01M

The many rows of sharp, jagged teeth on some sharks is an example of an

Answers

Maybe venus fly trap

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