MATHEMATICS HIGH SCHOOL

Solve the equation for y
6x+y=5

Answers

Answer 1
Answer: 6x + y = 5
adding -6x on both sides
y = -6x + 5 Answer

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Solve the system using substitution.

y=6x-11
-2x-3y=-7

Answers

26=16x or x=1 5/8 because 6 and 11 are multiplied by 3
-2x - 3(6x - 11) = -7 Plug in the equation
-2x -18x + 33 = -7 Combine like terms
-20x + 33 = -7 Subtract
-20x = -40 Divide
x = 2

Hope this helps!!!

Which set of integers is included in (-1,3]?

Answers

the answer could be 0 , 1 , 2 , 3 hope this helps!

Suppose AP = 2 cm and BQ = 7 cm. What is the length of PC?

Answers

Step-by-step explanation:

is this a quadrilateral? or polygon or triangle?

what are the angles (I believe there should be at least an angle given) else PC can be any value that is positive

Josef ate 1/4 a pizza in 1/2 an hour. How much pizza would Josef eat in one hour?

Answers

1/2 of the pizza is eaten in an hour. To get from 1/2 an hour to 1 hour, you multpily by 2. Multiply 1/4 by 2 to get 1/2.

Please tell me if this is right please

Answers

Yea I think so I’m pretty sure

Answer: I think this is right

You work for a small business that sells bicycles, tricycles, and tandem bicycles (bicycles built for two). Bicycles have one seat, one front-steering handlebars, two pedals , and two wheels. Tricycles have one seat, one front-steering handlebars, two pedals, and three wheels. Tandem Bicycles have two seats, one front-steering handlebars, four pedals, and two wheels. Part A: On Monday, you counted forty-eight tricycle wheels. How many tricycles were in the shop? Write an algebraic equation that shows the relationship between the number of wheels (w) and the number of tricycles (t). Part B: On Wednesday, there were no tandem bicycles in the shop. There were only bicycles and tricycles. There were a total of twenty-four seats and sixty-one wheels in the shop. How many bicycles and how many tricycles were in the shop? Solve algebraically and show all your work. Let a = the number of tricycles Let b = the number of bicycles Part C: A month later, there were a different number of bicycles, tricycles, and tandem bicycles in the shop. There were a total of 144 front-steering handlebars, 378 pedals, and 320 wheels. How many bicycles, tricycles, and tandem bicycles were in the shop? Solve algebraically and show all your work. Let a = the number of tricycles Let b = the number of bicycles Let c = the number of tandem bicycles.

Answers

Part A: each tricycle has three wheels, so with 48 wheels the number of tricycles was a =48/3=16 tricycles.
t=w/3 (the number of tricycles is the number of wheels divided by 3)

Part B:
The number of seats:
24=b+a (so b=24-a)
The number of seats is the sum of one seat per bicycle and one seat per a tricycle

also, 61=2a+3b (the number of wheels)

So we have:
24=b+a
 b=24-a
We can substitute this for b:

61=2a+3(24-a)

and solve:
61=2a+3*24-3a
61=72-a
a=72-61
a=11

There were 11 bicycles!!
and there were 24-11 tricycles, so 13 tricycles.

Part C: each of the bikes has only one  front-steering handlebar, so there were a total of 144 vehicles:

a+b+c=144

There were 378 pedals. And the number of pedals is:
2a+2b+4c=378 (the numbers 2,2,4 represent the number of pedals per vehicle)

divide by 2:
a+b+2c=189

Now, we have
a+b+2c=189
and

 a+b+c=144
and we can subtract them from each other:
a+b+c-(a+b+2c)=144-189
-c=45
c=45, so there were 45 tandem bicycles!
(this also means that a+b=144-45, that is a+b=99)
now the wheels:
3a+2b+2c=320
Let's substitute c:
3a+2b+90=320

which is
3a+2b=240
We also know that a+b=99, so we can substract this from this equation:
3a+2b+-a-b=240-99
2a+b=141

and again:
2a+b-a-b=141-99
a=42 - there were 42 trycicles!!!

And the bicycles were the rest:
99-42=57 bycicles
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