The perimeter of the rectangle is 34 1/8 inches. To find it, you converted the mixed number dimensions to improper fractions, used the perimeter formula, and simplified the result to a mixed number.
To find the perimeter of a rectangle, you can use the formula P = 2(l + w), where P represents the perimeter, l is the length, and w is the width.
In this case, the length of the rectangle is 10 3/16 inches, and the width is 6 7/8 inches. To add mixed numbers, first convert them to improper fractions for easier calculation.
Length:
10 3/16 = (10 * 16 + 3) / 16 = 163/16 inches
Width:
6 7/8 = (6 * 8 + 7) / 8 = 55/8 inches
Now, plug these values into the formula:
P = 2(163/16 + 55/8)
Now, find a common denominator, which is 16:
P = 2((163/16) + (110/16))
Now, add the fractions:
P = 2(273/16)
Multiply the sum by 2:
P = (2 * 273)/16 = 546/16
Now, simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 2:
P = (546/2)/(16/2) = 273/8
So, the perimeter of the rectangle is 273/8 inches. To express it as a mixed number:
273/8 = 34 1/8 inches
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The result after subtracting 8 from the quotient of 15 and 3, -3
When we divide one number by another, the result is a quotient. As an instance, when we divide 8 by 4, we obtain the answer 2, which is the quotient. A decimal or an integer can both be used as the quotient. When dividing exactly, as when 10/5 = 2, the quotient is an integer, whereas when dividing roughly, as when 3/2 = 1.5, the quotient is a decimal. Although a quotient might be more than the divisor, it will never be greater than the dividend.
Given that,
Two numbers, 15 & 3
Another number 8 for subtraction
The value after subtraction of 8 from the quotient of 15 and 3 = ?
First step- the quotient of 15 and 3
⇒ 15/3
⇒ 5
the quotient of 15 and 3 is 5
Second step-
Subtracting 8 from the quotient,
⇒ 5 - 8
⇒ -3
Hence, the result is -3
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The number Of households with VCRs in 1990 was about 87.5% of the number with VCRs in 1993. About how many households had VCRs in 1993? 1989 ~ 1 household 1985 ~ 18 households 1990 ~ 63 households 1995 ~ 77 households
Answer
the is D
Step-by-step explanation: