1 . A farmer moves along the boundary of his rectangular field of side 10m x 20m . farmer covers 1m in 1sec . what will be the magnitude of displacement at the total distance travelled.2 . Rahul pedals his cycle from rest. Pedals his cycle to get a
velocity of 10 ms-1 in 30 seconds.
then he applies brakes in such that the velocity of the cycle comes does to 6
ms-1 in next 5 seconds . calculate
the acceleration and deceleration .

Answers

Answer 1

Answer: 1). He's walking the 'perimeter' of his field, meaning 'the distance all the way around'.
If he stays right along the fence all the way, then the total distance he walks is
(10 + 20 + 10 + 20) = 60 meters. (It's a small field ... about 5% of an acre.)
The magnitude of displacement is the distance between the start point and end point,
regardless of the route. After he finishes one whole trip around, his displacement is
zero, because he ends up at the same place where he started.
Notice the big fat red herring in the question: None of this depends on the speed
at which he walks.

2). Acceleration = (change in speed) / (time for the change)

While speeding up, acceleration = (10 - 0) / 30 = 1/3 meter per second².

While slowing down, deceleration = (6 - 10) / 5 = -4/5 = -0.8 meter per second²

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How are forces able to act at a distance ?

Answers

Magnetic forces act at a distance. The opposites attract and pull each other closer

A car is traveling at 20 m/s. It takes the car 120s to go from one intersection to a second. What was the displacement of the car between the two intersections?

Answers

We don't know if the road is perfectly straight between the intersections, or if the road bends, curves, or turns between them. So we don't have enough information to calculate the displacement between them.

But we can calculate the distance the car traveled between them.

Distance = (speed) (time)

Distance = (20 m/s) (120 s)

Distance = 2,400 meters

If the velocity of a body varied uniformly from 10 ms-1 to 25 ms-1 during a time interval of 5s what was the acceleration of the body?

Answers

Acceleration = velocity change / time
a = 25 - 10 / 5
a = 15/5
a = 3

In short, Your Answer would be 3 m/s2

Hope this helps!

Acceleration of the body =

.

Hope this cleared your doubt. Have a great day/night ahead!

If you are following a car and also being tailgated by another vehicle, your best option would be to.. a. Increase the following distance between you and the car in front of you b. Slam on your breaks immediately c. Speed up to increase the space between you and the tailgating car d. Slowly and steadily apply your breaks

Answers

Answer:

D. Slowly and steadily apply your breaks.

Explanation:

When a person is being tailgated by another vehicle there's a risk of accident, due to the difference of speeds. When someone is being tailgated by another vehicle, it's because they vehicle doesn't work, cannot move by itself, so one vehicle impulse another.

To avoid any accident, the vehicle that's being tailgated must apply breaks often and slowly to try to maintain the same constant distance and speed than the other vehicle. This constant distance is what avoid accidents.

Therefore, the right answer is D.

Answer:

Your answer here is D

Explanation:

Slowly pressing your breaks will help ensure you are not hit by the other car. If they hit you its their fault. Hope this helps :)!

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