What are the two ordered pairs for 5x=-1

Answers

Answer 1

Answer: 5x = -1

x = -1/5 = -0.2

That means that any ordered pair for the line will be (-0.2, y)

You can put any number in for y.

So two ordered pairs could be:

(-0.2, 1)
and
(-0.2, 2)

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5(t+3)+2(3t+4)-(5t-3)

Answers

5(t+3)+2(3t+4)-(5t-3)
First, you need to use the distributive property.
5t+15+6t+4-5t+3
Next, you add/subtract like terms
5t+6t-5t=6t
15+4+3=22
So, you are left with:
6t+22

Hope this helped! If you have any other questions pertaining to this, please ask!

The answer is 6t + 26 In the process of solving this problem you will use mathematical properties , adding , subtracting , dividing , and simplifying.

My reason being is because , 1st you solve | 2 *3t + 13 , than look at the equation again :

it's really , (5*3t) + 2 *( (3t+4) ) - ( 5t - 3 ) . This is how I got my answer , by pulling out like terms , which happen to be : 6t + 26 = 2 * (3t+13).

The last step to the answer is below :

2 * (3t + 13) .

I really hope that this helps you out a lot, have a nice day :)

What is the equation of a line that is parallel to the line x=14 and contains the point (-3,7)?

Answers

Answer:

x = -3

Step-by-step explanation:

The line x=14 is a vertical line. The line you want must also be a vertical line. In order for it to go through the given point, the constant in the equation must match the x-coordinate of the point: -3.

x = constant . . . . equation of a vertical line

x = -3 . . . . . . . . . . equation of your vertical line

Write the equation of the given line in standard form y=ax+b:The line containing the midpoints of the legs of a right triangle ABC where A (-5,5), B (1,1) and C (3,4) are the vertices.

Answers

Find the distance between the sets of points.
Use this to determine which sides are the legs.

A to B = sqrt(52) = 7.2111
A to C = sqrt(50) = 7.07106
B to C = sqrt(65)= 8.622577

B to C is hypotenuse

midpoint of A to B is (-2,3)
midpoint of A to C is (-1, 4.5)

The line we are solving for contains these midpoints, so we have to solve for the slope between them and use point-slope form to make the equation of the line.
slope = 3/2 (or 1.5)
y=m(x-x1)+y1

y=3/2(x- (-2)) +3

y=3/2x+6

How do you factor this 8x^2+2x-21=0

Answers

$8x^2+2x-21=0 \n \n 8x^2+2x + 12x -12x-21=0\n\n8x^2+ 14x -12x-21=0 \n \n 2x(4x+7)-3(4x+7)=0\n\n(4x+7)(2x-3)=0$

$4x+7=0 \ \ or \ \ 2x-3 =0 \n\n4x=-7\ \ or \ \ 2x=3\n\nx=(-7)/(4)\ \ or \ \ x=(3)/(2)$

Solve it like this..
8x^2+2x-21=0
8x^2 + 14x - 12x -21=0
2x(4x+7) -3(4x+7) = 0
(4x+7)(2x - 3)=0

So factor 1 is 4x +7 =0
i.e. x=-7/4

Factor 2 is 2x -3 =0
i.e x=3/2

Determine if the equations are parallel, perpendicular, or neither.5x + 3y = 3 and 3x + 5y = -25