Do any one know what is number language

Answers

Answer 1

Answer: an arthemitatical value represented by symbols and numbers

Related Questions

Why is it helpful to draw a picture when attempting to solve an equationPLEAS HELP ME I GIVE THANKS
How do you explain 87% of 55?
Al's Awesome Autos advertised a special sale on cars - Dealer cost plus 5%!! jack and Margaret bought a luxury sedan for $23,727.90.what was the dealers cost? please answer! it's for an important packet
Carl has 200 songs on his MP3 player o these songs 24 are country songs. What percent of Carl's songs are country songs? please explain how you would do this problem!
What number is 16% of 95

9 lb equals how many ounces

Answers

144 because 1 pound is 16 oz so 16 times 9 equals 144

144 ounces are in 9 pounds because there are 16 ounces in 1 pound so you would do 16*9 which equals 144

Which shows one way to determine the factors of x3 + 4x2 + 5x + 20 by grouping?Which shows one way to determine the factors of x3 + 11x2 – 3x – 33 by grouping?

Answers

Answer:

1). (x² + 5) and (x + 4)

2). (x²- 3) and (x + 11)

Step-by-step explanation:

We have to determine the factors of the given expression (x³ + 4x² + 5x + 20) by grouping method.

x³ + 4x² + 5x + 20

= x²(x + 4) + 5(x + 4)

= (x² + 5)(x + 4)

Therefore, factors of the given expression are (x² + 5) and (x + 4).

Second expression is (x³ + 11x² - 3x - 33)

Now we will find the factors of this expression by grouping.

x³ + 11x² - 3x - 33

= x²(x + 11) - 3(x + 11)

= (x² - 3)(x + 11)

Therefore, the factors of the given expression are (x² - 3) and (x + 11).

Answer:

B x^2(x+4)+5(x+4)

Step-by-step explanation:

Edge2021

What is an equivelent expression for 4(x+5)+2(x+3)

Answers

4x+20+2x+6 is what you get when you distribute, just group the similar ones together and get 6x+26, that's the answer 6x+26

4(x+5)+2(x+3)
4x+20+2x+6
6x+26

The rule is applied to ΔFGH to produce ΔF"G"H".What are the coordinates of vertex F" of ΔF"G"H"?

(4, –1.5)
(4, –0.5)
(–1.5, 4)
(–0.5, 4)

ITS TIMED. I REALLY NEED HELP!!!