Find the pattern and use it to list the nth term in the sequence. 1, 1/32,1/243,1/1024,1/3125

Answers

Answer 1

Answer: $1;\ (1)/(32);\ (1)/(243);\ (1)/(1024);\ (1)/(3125)\n\n1=(1)/(1^5)\n\n(1)/(32)=(1)/(2^5)\n\n(1)/(243)=(1)/(3^5)\n\n(1)/(1024)=(1)/(4^5)\n\n(1)/(3125)=(1)/(5^5)\n\vdots\n\na_n=(1)/(n^5)\ where\ n\in\mathbb{N^+}$

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Solve the equation, check for extraneous solutions x-10= √9x please explain each step with words:)

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Reduce to lowest term18/24

Answers

a common number is 6 so divide 18 and 24 by 6. you get the total of 3/4

18/24

Find the HCF of the numerator and denominator and divide them by it.

In this case, its 6

18/24 ÷ 6/6 = 3/4

Frank, Mary and Seth shared some sweets in the ratio 4:5:7.Seth got 18 more sweets than Frank.

Work out the total number of sweets they shared.

Answers

The ratio of the sweets shared: F : M : S : : 4 : 5 : 7 The total of the ratios: 16 The ratio difference (3) between S and F equals 18 sweets. Hence the total number of sweets they shared is 96.

What is the value of x?
Enter your answer in the box

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Answer:

could we have a picture or the equation?? plz

Answer:

is there any more to the question??

Find the inverse of each function1) g (x)= 3+(x-1)^3
4) f (x)=x^3+2
5) f (n)= 5 square root of (-n+1/2)

Answers

to find the inverse
1. replace f(x) or g(x) or f(n) with y
2. switch places of x and y
3. solve for y
4. replace y with f⁻¹(x) or g⁻¹(x) or f⁻¹(n)

1.
g(x)=3+(x-1)^3
replace
y=3+(x-1)^3
switch
x=3+(y-1)^3
solve
x=3+(y-1)^3
subtract 3
x-3=(y-1)^3
cube root both sides
$\sqrt[3]{x-3}$ =y-1
add 1
$\sqrt[3]{x-3}$ +1=y
switch y with g⁻¹(x)
g⁻¹(x)= $\sqrt[3]{x-3}$ +1

4. f(x)=x^3+2
replace with y
y=x^3+2
switch x and y
x=y^3+2
solve for y
x=y^3+2
subtract 2
x-2=y^3
cube roo both sides
$\sqrt[3]{x-2}$ =y
replace with f⁻¹(x)
f⁻¹(x)= $\sqrt[3]{x-2}$

5.
f(n)=5 $√(-n+1/2)$
replace
y=5 $√(-n+1/2)$
switch n and y
n=5 $√(-y+1/2)$
solve for y
n=5 $√(-y+1/2)$
divide both sides by 5
n/5=n= $√(-y+1/2)$
square both sides
$(n^2)/(25)$ =-y+1/2
subtract 1/2 from both sides
$(n^2)/(25)$ - $(1)/(2)$ =-y
multiply both sides by -1
- $(n^2)/(25)$ + $(1)/(2)$ =y
replace with f⁻¹(n)
f⁻¹(n)=- $(n^2)/(25)$ + $(1)/(2)$

1. g⁻¹(x)= $\sqrt[3]{x-3}$ +1
4. f⁻¹(x)= $\sqrt[3]{x-2}$
5. f⁻¹(n)=- $(n^2)/(25)$ + $(1)/(2)$

The mean of a population being sampled is 64, and the standard deviation is 6. If the sample size is 50, the standard error of the mean is

Answers

The standard error of the mean is viewed as the standard deviation of the error in the sample mean in relation to the true mean. It is expressed as the ratio of the sample standard deviation and the square root of the sample size.

SE = s / √n
SE = 6 / √50
SE = 0.85

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