Answer: Hello mate!
Ok, the 6 sides cubes can be thinked as two normal dice.
A fair game is that game where both players have the same chance to win, first, let's calculate the situations where you friend win:
this are, if the cubes have numers between 1 and 6:
1 + 6
6 + 1
2 + 5
5 + 2
3 + 4
4 + 3
where 1 + 6 is different to 6 + 1 because in the first one you rolled a 1 and your friend a 6, and in the second one you rolled a 6 and your friend a 1, so are different events.
Then you can see that you friend has 6 combinations where he wins.
So we need to find two numbers that between them, have the same number of combinations.
I can think, for example in 4 and 10:
the combinations for 4 are:
2 + 2
3 + 1
1 + 3
a total of 3 combinations:
for 10 are:
5 + 5
4 + 6
6+ 4
also 3 combinations.
So if you win a point if the sum is 4 or 10, you also have 6 combinations where you win, then the game is fair
Now, suppose the first number is 5, let's find the second:
the combinatios for 5 are:
4 + 1
1+ 4
2 + 3
3 + 2
a total of 4 combinations, this means that we need to find another number that only has two combinations, wich can be, for example, 3
the combinations for 3 are:
1 + 2
2 + 1
2 combinations, then if your numbers are 3 and 5, you have 6 combinations where you win, and the game is fair.
5 yd
5 yd
a
500 yd2
О Б
100 yd2
Oc
50 yd?
Od
200 yd?
Answer:
a- 500yd^3
Step-by-step explanation:
volume=lwh
=5x5x20
=500
brainliest appreciated!!
The answer is B. 5(x + 5) = 353 + x
(For anyone who needs it now)
Answer: B. 5(x + 5) = 353 + x
Step-by-step explanation:
9/12 + 6/12
Fall League Soccer & Year
Year & # of Participants