How do you count by ones from 368 to 500 change for a larger unit when necessary

Answers

Answer 1

Answer: 500 - 368 = 132
This means that to reach 500 from 368, you will need to count 132 ones.

132 can be written in several ways including:
132 = 100 + 32
132 = 100 + 30 + 2

For the first one:
the count will be 1 one hundred and 32 units to reach 500 from 368

For the second one:
the count will be one hundred, 30 tens and 2 ones to reach 500 from 368

Answer 2

Answer:

In order to reach a count of $500$ from $368$ we need to count $\fbox{\begin\n\ \bf 132 \text{one's}\n\end{minispace}}$ .

Further explanation:

The problem is based on counting.

As per the International Numeral System the first digit is at one's place, second digit is at ten's place, third digit is at hundred's place.

In any number each digit has its place value and a face value.

Face value of any digit is its actual value of the digit.

For example: In a number $234$ the face value of the digit $4$ is $4$ and the face value of the digit $3$ is $3$ .

Place value of any digit in a number is the value represented by the digit as per the position of the digit in the number.

For example: In a number $234$ the place value of the digit $4$ is $4$ , place value of the digit $3$ is $30$ and the place value of the digit $2$ is $200$ .

In this question it is asked to determine a way to count by one's from $368$ to $500$ .

The difference between the number $368$ and $500$ is calculated as follows:

$\fbox{\begin\n\ 500-368=132\n\end{minispace}}$

The number $132$ is read as one hundred and thirty two.

The number $132$ is represented as follows:

$\fbox{\begin\n\ 132=100+30+2\n\end{minispace}}$

This implies that the digit $2$ is at one's place, digit $3$ is at ten's place and the digit $1$ is at hundred's place.

From figure 1 (attached in the end) it is observed that $10$ unit of one’s is equivalent to $1$ unit of ten's and $10$ unit of ten's is equivalent to $1$ unit of hundred's.

So, as per the above statement it is concluded that to reach a count of $500$ from $368$ we need to count $132$ one's.

Thus, in order to reach a count of $500$ from $368$ we need to count $\fbox{\begin\n\ \bf 132 \text{one's}\n\end{minispace}}$ .

Learn more:

1. A problem on composite function brainly.com/question/2723982

2. A problem to find radius and center of circle brainly.com/question/9510228

3. A problem to determine intercepts of a line brainly.com/question/1332667

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Counting

Keywords: Counting, count, one's, ten's, hundred's, 368, 500, numeral, numeral system, International numeral system, face value, place value, digit, number.

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A city doubles its size every 29 years. If the population is currently 300,000, what will the population be in 58 years?

Answers

Answer:

1,200,000 or 900,000

Step-by-step explanation:

what i did was subtract 29 from 58 until i couldn't so 58-29=29 then 29-29=0 that 2. then i did 300,000*2=600,000. now if we double again like it says every 29 years then its 600,000*2=1,200,000. or you do 300,000+300,000=600,000 then 600,000+300,000=900,000

One less than the quotient of a number n and 6

Answers

Step-by-step explanation:

Please resend with the full question

the price of a bike after a discount was $250. If the discount was 60% how much was the original cost of the bike?

Answers

Answer is:249.96 equally to 250

Explanation:250×100=25000

25000÷60=416.6

416.6×60=24,996

24,996×100=249.96

Final answer:

In order to calculate the original cost of a discounted item, you can adjust the discounted price by dividing it by 1 minus the discount percentage. Therefore, using this method, the original cost of a bike which cost $250 after a 60% discount was $625.

Explanation:

The given question refers to a situation where a bike has been bought for $250 after a discount of 60%. In such a scenario, we want to find out the original cost of the bike before the discount was applied.

To get the original price, we will adjust the equation for the discount, which is Original Price = Discounted Price / (1 - Discount Percentage).

Here, replacing the values / variables provided in the question into the equation, we get:
Original Price = $250 / (1 - 0.60) = $250 / 0.40 = $625.

Therefore, the original cost of the bike was $625.

Learn more about Percentage calculation here:

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Explain why P(A|D) and P(D|A) from the table below are not equal.

Answers

Answer:

The two conditional probabilities are not equal because each has different given events. P(A|D) has event D as its given event, resulting in 2/10 for a probability. P(D|A) has event A as its given event, resulting in 2/8 for a probability.

Other part is:

different given events

P(A|D) equals 2/10

P(D|A) equals 2/8

because they are in different positions which make them different answers/number

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Answers

It would be the number from the new game with the fewer than sign than the number from the last game. So for example n>78

Which expression is equivalent to

Answers

Answer:

the expression is equivalent to x^2/3

Step-by-step explanation:

[x^4/3 x^2/3]^1/3

=[x^4/3+(2/3)]^1/3

by using laws of exponent

a^m a^n=a^m+n

=[x^4/3+2/3]^1/3

=[x^6/3]^1/3

={x^2]^1/3

by using law of exponent

(a^m)^n=a^mn

=x^2×1/3

=x^2/3

i hope this will help you :)

Answer:

x^2/3

option B is the right option

solution,

$( {x}^{ (4)/(3) } . {x}^{ (2)/(3) }) ^{ (1)/(3) } \n = ({x ^{ (4)/(3) + (2)/(3) } )}^{ (1)/(3) } \n = ({x}^{ (4 + 2)/(3) } ) ^{ (1)/(3) } \n = ( {x}^{ (6)/(3) } ) ^{ (1)/(3) } \n = {x}^{ (6 * 1)/(3 * 3) } \n = {x}^{ (6)/(9) } \n divide \: 6 \: and \: 9 \: by \: 3 \n = {x}^{ (2)/(3) }$

hope this helps...

Good luck on your assignment...

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