A.
negative linear association
B.
negative nonlinear association
C.
positive linear association
D.
positive nonlinear association
f. Would you still use the same domain and range? Why or why not?
Answer:
a) The domain of the function is . , , b)The range of the function is . , , c) The ball is 73 meters off of the ground at x = 3 seconds.Step-by-step explanation:The complete statement is: A ball is thrown upward off of a 100 meter cliff with an initial velocity of 6 m/s. The function represents this situation where x is time and y is the distance off of the ground. a) What domain does the function make sense? b) What range does the function make sense ? c) How far off the ground is the ball at time x = 3 seconds?a) Let and be the time, measured in seconds, and the distance of the ground, measured in meters, respectively. Time is a positive variable, so domain corresponds to the interval when and . That is: Therefore, the domain of the function is . , b) The distance off of the ground is also a positive variable, where ball is thrown upward at a height of 100 meters and hits the ground at a height of 0 meters. Hence, the range of the function is . , c) The distance of the ball off of the ground at x = 3 seconds is found by evaluating the function:The ball is 73 meters off of the ground at x = 3 seconds.
Step-by-step explanation:
y - x < 2x + 2
To isolate y, let's add both sides by x.
y - x + x < 2x + 2 + x
y < 3x + 2
That should be your answer for the equation. For the graph, look at the image I attached to my answer~
Happy Studying~
Answer:
y < 3x+2
Step-by-step explanation:
Two possible answers are:
Rounding to the nearest ten, we have 590-320 = 270; rounding to the nearest hundred, we have 600-300 = 300.
Explanation:
When estimating, we can round the number to different places. Both numbers are in the hundreds place. This means we can round to either the hundreds or the tens place.
Rounding 586 to the tens place, 8 is in the tens place. Looking behind it, we have a 6; this means we round the 8 up to 9, and have 590.
Rounding 321 to the tens place, 2 is in the tens place. Looking behind it, we have a 1; this means we keep the 2 and have 320.
590 - 320 = 270.
Rounding 586 to the hundreds place, 5 is in the hundreds place. Looking behind it, we have an 8; this means we round the 5 up to 6 and have 600.
Rounding 321 to the hundreds place, 3 is in the hundreds place. Looking behind it, we have a 2; this means we keep the 3 and have 300.
600-300 = 300.
Move the digit to the thousand place so that it's value is 10 times greater.
Given that,
A digit is in the hundreds place. The digit is moved so that its value is 10 times greater. To which place it move is to be determined.
The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.
Let the digit be 1 on the hundred places, and digits on ten and unit place are 0, 0,
So the number is 100
Now the digit on the hundred place shift to a thousand places and the place vacant on the hundred places is filled by another 0.
Now the number is 1000,
Dividing later number to the former number i.e.
= 1000 / 100
= 10
Thus, move the digit to the thousand place so that it's value is 10 times greater.
Learn more about simplification here: brainly.com/question/12501526
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y=2x+8
substitution method
Answer:
No Solution.
Step-by-step explanation:
2(x-1)-y=-8
y=2x+8
----------------
2x-2-(2x+8)=-8
2x-2-2x-8=-8
2x-2x-2-8=-8
0-2-8=-8
-2-8=-8
-10=-8
no solution