A water cooler fills 150 glasses in 30 min. how many glasses of water can the cooler fill per minute

Answers

Answer 1
Answer:

The number of glasses of water the cooler can fill per minute is 5 glasses

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of glasses of water the cooler can fill per minute be = A

Now , the equation will be

The number of glasses of water the cooler can fill = 150 glasses

The time required by the cooler to fill 150 glasses = 30 minutes

So , the equation is

The number of glasses of water the cooler can fill per minute = number of glasses of water the cooler can fill  / time required by the cooler to fill 150 glasses

Substituting the values in the equation , we get

The number of glasses of water the cooler can fill per minute = 150 / 30

The number of glasses of water the cooler can fill per minute = 5 glasses

Therefore , the value of A is 5 glasses

Hence ,

The number of glasses of water the cooler can fill per minute is 5 glasses

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Answer 2
Answer:
you do 150 divided by 30, which would equal 5 glasses.

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Which point represent 110 on the number line below

Answers

the answer is point r 85+25=110 Point R

Mason drew a quadrilateral with only one pair of opposite sides that are parallel. What quadrilateral did Mason draw?

Answers

Answer:

Trapezoid.

Step-by-step explanation:

Given that Mason drew a quadrilateral with only one pair of opposite sides that are parallel

We know that a quadrilateral is a closed region bounded by four lines called sides with four angles totalling 360 degrees.

Some special types of quadrilaterals are squares, rectangles, parallelograms, trapezoids, etc.

When all four sides and four angles are equal square.  When only angles are equal, rectangle.  When all four sides are only equal, rhombus. A trapezium is a quadrilateral with only one pair of sides parallel

Hence here what Mason drew is a quadrilateral.

Mason drew a trapezoid.

Describe 58 as a sum of tens and ones

Answers

58 is 5 tens (5*10) and 8 ones (8*1)

What is the supplement of a 76 degree angle?

Answers

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Simplify a raised to the negative third power over quantity 2 times b raised to the fourth power end quantity all cubed.8b12a9
quantity 8 times b raised to the twelfth power end quantity over a raised to the ninth power
1 over quantity 6 times a raised to the ninth power times b raised to the twelfth power end quantity
1 over quantity 8 times a raised to the ninth power times b raised to the twelfth power end quantity

Answers

Answer:

(1)/(8a^9b^12)

Step-by-step explanation:

((a^(-3))/(2b^4))^3 =

= ((1)/(2a^3b^4))^3

= (1)/(8a^9b^(12))

Answer:To simplify the expression "a raised to the negative third power over quantity 2 times b raised to the fourth power end quantity all cubed", we can follow these steps:

Step 1: Simplify the numerator.

a raised to the negative third power is equivalent to 1 over a cubed.

Step 2: Simplify the denominator.

2 times b raised to the fourth power is equivalent to 2b to the fourth power.

Step 3: Combine the simplified numerator and denominator.

So, the expression becomes 1 over a cubed divided by 2b to the fourth power, all cubed.

Step 4: Simplify the division.

When we divide by a fraction, we can multiply by its reciprocal.

The reciprocal of 2b to the fourth power is 1 over 2b to the fourth power.

Therefore, the expression simplifies to 1 over a cubed times 1 over the reciprocal of 2b to the fourth power, which is 1 over 2b to the fourth power.

In summary, the simplified expression is 1 over 2b to the fourth power times a cubed.

PLEASE HELP ASAP I NEED THIS NOW Sara graphs a line passing through points that represent a proportional relationship. Which set of points could be on the line that Sara graphs?A). (2,4),(0,2),(3,9)
B). (6,8),(0,0),(18,24)
C). (3,6),(4,8),(9,4)
D). (1,1),(2,1),(3,3)​

Answers

Answer: Option B.

Step-by-step explanation:

By definition, the graph of a proportional relationships is a straight line that passes through the origin (Remember the the origin is at (0,0)).

Then, the equation have the following form:

y=kx

Where "k" is the constant of proportionality (or its slope)

Then, since the Sara graphs a line that represent a proportional relationship, you can conclude that the line must pass through the point (0,0).

Then:

The set of points in Option A could not be on that line, because when x=0,y=2

The set of points (6,8),(0,0),(18,24) (Given in Option B) could be on the line that Sara graphs, because it has the point (0,0)

For the set of points shown in Option C and Option D, you can check if the slope is constant:

C)\ slope=(y)/(x)\n\na)\ slope=(6)/(3)=2\n\nb)\ slope=(8)/(4)=2\n\nc)\ slope=(4)/(9)

Since the slope is not constant, this set of ponts could not be on the line.

 D)\ slope=(y)/(x)\n\na)\ slope=(1)/(1)=1\n\nb)\ slope=(1)/(2)

 Since the slope is not constant, this set of ponts could not be on the line.

Set of points that could be on the line that Sara graphs are:

Option B). (6,8) , (0,0) , (18,24)

Further explanation

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

m → gradient of the line

( 0 , c ) → y - intercept

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = (y_2 - y_1)/(x_2 - x_1)}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )}}

Let us tackle the problem.

\texttt{ }

This problem is about Directly Proportional.

If (x₁ , y₁ ) and (x₂ , y₂) are on the line that represent a proportional relationship, then :

\large {\boxed { y_1 : x_1 = y_2 : x_2 } }

Option A

Let:

(2,4) ⇒ (x₁ , y₁)

(3,9) ⇒ (x₂ , y₂)

4 : 2 \ne 9 : 3

2 : 1 \ne 3 : 1

2 \ne 3not proportional

\texttt{ }

Option B

Let:

(6,8) ⇒ (x₁ , y₁)

(18,24) ⇒ (x₂ , y₂)

8 : 6 = 24 : 18

4 : 3 = 4 : 3proportional

\texttt{ }

Option C

Let:

(3,6) ⇒ (x₁ , y₁)

(9,4) ⇒ (x₂ , y₂)

6 : 3 \ne 4 : 9

3 : 1 \ne 4 : 9not proportional

\texttt{ }

Option D

Let:

(1,1) ⇒ (x₁ , y₁)

(2,1) ⇒ (x₂ , y₂)

1 : 1 \ne 1 : 2not proportional

\texttt{ }

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Answer details

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

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