Answer:
66.67 ml of 5% solution and 133.33 ml of 6.5% solution are mixed.
Step-by-step explanation:
Let 200 ml of 6% solution is formed by mixing x ml of 5% solution and y ml of 6.5% solution.
We can write the equation x + y = 200 ........ (1)
Now, x ml of 5% solution will contain ml of acid
Again, y ml of 6.5% solution will contain ml of acid.
So, mixing them together will give (0.05x + 0.065y) ml of acid in 200 ml of solution.
So, from the condition given we can write
⇒ 0.05x + 0.065y = 12
⇒ x + 1.3 y = 240 ........... (2) {Dividing both sides by 0.05}
Now, solving equations (1) and (2), we get
0.3y = (240 - 200) = 40
⇒ y = 133.33 ml
From equation (1) we get, x = 200 - 133.33 = 66.67 ml
Therefore, 66.67 ml of 5% solution and 133.33 ml of 6.5% solution are mixed. (Answer)
Answer:
1 hour and 45 minutes
Step-by-step explanation:
as I can see this the answer is
x = 25/78
in decimal
x = 0.320
The problem involves joint variation with variables y, x, and z. After finding the constant of variation, we substitute the given values into the joint variation equation and determine that x = 16.67
First, we establish the equation of joint variation, which in this context is y = kxz, where 'k' is the constant of variation. When y=13, x=26, and z=6, we insert these values into the equation to solve for 'k'. This gives us k = y/(xz) = 13/(26*6) = 0.08333.
Now that we have the constant 'k', we can find the value of 'x' when y=25 and z=18. We rearrange our equation to solve for 'x', resulting in x = y/(kz). Substituting the known values, we get x = 25/(0.08333*18) = 25/1.5 = 16.67. Therefore, if y varies jointly with x and z, and y=25 when z=18, then x = 16.67.
#SPJ2
3 arrays - 1 x 9 (or 9 x 1) and 3 x 3
Hence, the number of arrays = 2 x 2 = 4 = even
First, we pair the different factors of 9.
The different factors of 9 are:
(1, 9) and (3, 3)
For each pair, Mr. Deets can make 2 arrays.
So, the total number of arrays that Mr. Deets can make = 2 x 2 = 4 and hence the number of arrays is even.
Answer:
4 arrays,
Number of arrays is even.
Step-by-step explanation:
∵ The possible pairs of two numbers which give 9 after multiplication,
( 3, 3) and (9, 1),
So, the possible array would be,
3 × 3, 9 × 1
Note : 9 × 1 can also be written as 1 × 9,
According to the question,
For each pair of different factors, there are two arrays,
3 × 3 and 9 × 1 are two arrays with no same factor,
Hence, the total arrays = 2 × 2 = 4
Which is an even number.