A pound of seedless red grapes costs $2.75. Drew must spend less than $9.35 on a bunch of seedless red grapes.Inequality:

Solution:

Interpretation:

Answers

Answer 1
Answer: $2.75x > $9.35

$9.35/$2.75=3.4 lbs.

Drew can buy 3 lbs of seedless grapes for less than $9.35.
Answer 2
Answer:

Inequality:          x = the number of pounds of grapes

2.75x < 9.35     [2.75x is less than 9.35, since Drew must spend less than $9.35]

Solution:

To find the solution, you need to isolate/get "x" by itself in the inequality.

2.75x < 9.35   Divide 2.75 on both sides to get "x" by itself

(2.75x)/(2.75) <(9.35)/(2.75)

x < 3.4  

Interpretation:

x is less than 3.4, so Drew has to buy less than 3.4 pounds of grapes in order to spend less than $9.35 [which is the most/maximum $ he has]


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Answers

Rounding 3,397 to the nearest thousand would be 3,000 
It would be 3000 becuase round the 3 in the hundres place to the nearest place and it would be a zero

How do you draw one line in a triangle to make two new shapes?

Answers

Draw a line straight down the middle of the triangle.
you could draw a line down the middle of the triangle and get 2 triangles, but I don't know if you wanted different shapes. Hope I helped!

Photo above! How do I find the perimeter of this? I'm confused because no matter what I do the answers not right

Answers

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The way I look at Brainly, the whole purpose is to help guide you
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Clint bought 3 T-shirts at $9 each and 2 pairs of shorts at $12 each. Explain how to find the total Clint spent.

Answers

total cost=shirtcost+shortscost

shirtcost=number of shirts time cost per shirt
shirtcost=3 times 9=$27

shortscost=number of shirts times cost per short
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You need to use multiplication.

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A rectangle of perimeter 100 units has the dimensions shown. Its area is given by the function A = w(50 - w). What is the GREATEST area such a rectangle can have? The rectangle shown has 50-w on the top and bottom.
and a w on its left side and right side.

Answers

Answer:

The greatest area of rectangle is:

625 square units.

Step-by-step explanation:

It is given that:

A rectangle of perimeter 100 units has the dimensions as:

50-w on the top and bottom.

and a w on its left side and right side.

i.e. we may say the length of the rectangle is:

50-w

and the width of the rectangle is:

w

Now, we need to find the greatest area of rectangle.

As the area of rectangle is:

A = w(50 - w)=50w-w^2

Now, to find the maximum area we differentiate the Area with respect to the width as:

(dA)/(dw)=0\n\ni.e.\n\n50-2w=0\n\n50=2w\n\nw=25

Hence, to obtain the maximum area the width of the rectangle is: 25 units.

and that of the length of the rectangle is:

50-25=25 units.

Hence, the dimensions of rectangle in order to obtain the maximum area is:

25 units by 25 units.

So, the area of rectangle is:

Area=25* 25\n\nArea=625\ \text{square\ units}

Hence, the greatest area of rectangle is:

625 square units.

disregard the w and w-50 for now
to have the greatest area, try to make legnth and width the same
P=100
P=2(L+W)
100=2(L+W)
50=L+W
if L=W
50=L+L
divide 2
25=L=W

A=LW=25*25=625

greatest is 625 square units

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Answers

4*4*4*4*4*4= 4 to the 6th power!

46

the six is at the top right coner