Answer:
7
Step-by-step explanation:
add 6 to -6 to get 0
than add 1 to 0 to get 1
6+1=7
The distance between the points (-3,-6) and (-3, 1), both lying on the same vertical line, is found by subtracting their y-coordinates. The distance is 7 units.
The subject of this question is in the field of Math, specifically focusing on the concept of distance between two points in a plane. In this case, you are asked to find the distance between the points (-3,-6) and (-3, 1). The calculation is very straightforward as both points lie on the same vertical line where the x-coordinate of both points is -3. To find the distance between two points which lie on the same line , we can simply subtract the two y-coordinates.
So, the distance is given by the absolute value of the difference between the y-coordinates: |1 - (-6)| = |1 + 6| = |7| = 7.
So, the distance between (-3,-6) and (-3,1) is 7 units.
#SPJ3
B.(-2, 2) and (2,2)
C.(-3, -3) and (-3,3)
D.(-4,-4) and (4, 4)
Answer:
C.(-3, -3) and (-3,3)
Step-by-step explanation:
When we have a vertical line the slope is undefined.
That means the x values stay the same
C.(-3, -3) and (-3,3)
This has the same x values
m = (y2-y1)/(x2-x1)
=( 3- -3)/(-3 - -3)
(3+3)/(-3+3)
6/0
undefined
Answer: C
Step-by-step explanation:
2. The first term of a geometric sequence is -10,000 and the common ratio is -1/2. Find the 6th term.
3. The first term of a geometric sequence is 3/4 and the common ratio is 4. Find the 8th term.
Answer:
jenny gets $2 in change because $6 times 3 is 18 and 20-18 is 2. I hope this helps
Step-by-step explanation: