Part A: Solve −np − 90 < 30 for n. Show your work. Part B: Solve 5m − 3h = 45 for h. Show your work.

Answers

Answer 1
Answer: A.well to start you have to do  np + 90 >- 30
np > - 20
n > - 120/p

and for b
5m - 45 = 3h
so h = 5m/3 - 15

Related Questions

Write the symbolic form of the written expression given below. 1st in written expression, Then with the appropriate order of operations, Evaluate and simplify. 1. Three less than the product of thirteen squared and four. 2. The product of eight minus six and x. 3. The square root of thirty-six plus the sum of with and four squared. 4. Nineteen less than the product of seven and four minus the quotient of sixteen and four.
the expression 16t^2 models the distance in feet that an object falls during t seconds after being dropped. what distance will an object fall in 4 seconds?
Please help what is the answer its a math question find the lcd!!!
2: find the slop and the y-intercept of the line represented by the equation.7x + y = 8 I am having trouble with these, could someone please help me.
A = {0, 1, 2, 3}B = {a, b, c, d}C = {0, a, 2, b}Find B n C.

Hakim recorded his finishing time, in seconds, for each time he ran the 100 m race during one track season.What was the median of his finishing times?

12.0, 12.4, 11.9, 12.1, 12.2, 12.4, 12.1, 12.3, 11.9

Answers

its 12.1. it is the middle number from largest to least value.

What is 3 divided by 5/6

Answers

Answer:

3.6

Step-by-step explanation:

or infraction form 3 3/5

Answer:

3.6

Step-by-step explanation:

3÷5/6=3×6/5=18/5=3.6

The steamboat River Queen travels at the rate of 30km/h in still water. If it can travel 45 km up stream in the same amount of time that it takes to go 63 km down stream what is the rate of the current.

Answers

x-the\ rate\ of\ the\ current\nt-time\n\n \left\{\begin{array}{ccc}(30-x)t=45\n(30+x)t=63\end{array}\right\n \left\{\begin{array}{ccc}t=(45)/(30-x)\nt=(63)/(30+x)\end{array}\right\n\n(45)/(30-x)=(63)/(30+x)\n\ncross\ multiply\n\n63(30-x)=45(30+x)\n1890-63x=1350+45x\n-63x-45x=1350-1890\n-108x=-540\ \ \ \ /:(-108)\nx=5\n\nAnswer:The\ rate\ of\ the\ current\ is\ 5\ km/h.

Find the unknown length. Round to the nearest tenth if necessary.

Answers

Answer:

a = 7.4

Step-by-step explanation:

Since this is a right triangle, we will use the Pythagorean theorem:

c^2 = a^2 + b^2

28^2 = a^2 + 27^2

784 = a^2 + 729

55 = a^2

a = 7.4

Answer:

55 i believe

28 + 27 = 55

A blimp can be seen flying at an altitude of 5500 feet above a motor speedway during a race. The slanted distance directly to the pagoda at the startdashfinish line is d feet. Express the horizontal distance h as a function of d.

Answers

Answer:

The expression of h as function of x is   h = √((d + 5500) (d - 5500))

Step-by-step explanation:

Given as :

The distance of blimp  (AB) = 5500 feet

The slanted distance to the pagoda (BC) = d feet

The horizontal distance (AC) = h

Let the angle made between slanted distance and horizontal distance be Ф

So , cos Ф = (AC)/(BC) = (h)/(d)

And sin Ф =  (AB)/(BC) = (5500)/(d)

∵, cos²Ф = 1 - sin²Ф

So, ((h)/(d))^(2) = 1 - ((5500)/(d))^(2)

Or, ((h)/(d))^(2) = ((d^(2)- 5500^(2))/(d^(2)))

Or,                                     h² = d² - 5500²

∴                                        h = \sqrt{d^(2)- 5500^(2)}

Or,                                     h = √((d + 5500) (d - 5500))

Hence The expression of h as function of x is   h = √((d + 5500) (d - 5500))     Answer

3 to the power of 2-1+2(4(3+2))

Answers

Answer:68921

Step-by-step explanation:

This is what I think it is.