Identify the bond types between the carbon and the two oxygen Atoms in the carbon dioxide molecule.

Answers

Answer 1
Answer: The type of bond between the atoms in the carbon dioxide molecule is COVALENT BOND.
Covalent bond involves sharing of electrons between the atoms that are involved in the chemical reaction. The one carbon atom and the two oxygen atom that formed the carbon dioxide molecule share electrons in such a way that the outermost shell of each atom is made up of eight electrons.

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Why do minor parties have difficulty succeeding in the United States electoral system? A. tend to focus on only a single issue B. quickly join forces with the wrong party C. views are usually tied to strict religious doctrine D. seldom are given the respect from foreign officials they need to get elected

Answers

I think the best answer is D. Minor parties do not always get a support from foreign officials in order for them to get elected. They also have difficulties because they are a small political party. They do not have enough resources or supporters as compared to larger political parties.

Electrical motors work based on the fact that a wire carrying current can produce a ______________ field, which can lead to production of mechanical energy through rotation. A gravitational B parallel C magnetic D alternating

Answers

It’s C magnetic field because with the forces of the magnets pushing against each other it gets the engine to start turning the wheels.

What is required for reactants to form bonds? a. energy output
b. energy input
c. equilibrium
d. exchange reaction

Answers

a. Energy output 
since you need to release a certain amount of energy to hit the activation point.

In the following combustion reaction of acetylene (C2H2), how many liters of CO2 will be produced if 60 liters of O2 is used, given that both gases are at STP?2C2H2+5O2 2H2O+4CO2

The volume of one mole of gas at STP is 22.4 liters.

Answers

The stoichiometry of the reaction is 5 mols of O2 produces 4 mols of CO2.

1 mol at STP is equivalent to 22.4 liters.

So, 5*22.4 liters of O2 produces 4*22.44 liters of CO2

Then 60 liters of O2 produces 60*4/5 = 48 liters of CO2

Final answer:

In the combustion reaction of acetylene (C2H2), 60 liters of CO2 will be produced if 60 liters of O2 is used.

Explanation:

To determine the volume of CO2 produced in the combustion reaction of acetylene (C2H2), we need to use stoichiometry. From the balanced equation, we can see that 2 moles of C2H2 produce 4 moles of CO2. The ratio is 2:4 or 1:2. Given that 60 liters of O2 is used, we can assume the same volume of CO2 will be produced since both gases are at STP.

Therefore, the volume of CO2 produced would be 60 liters as well.

Keywords: combustion, volume, acetylene, O2, CO2, STP

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Why is helium used in airships rather thaan the other nobles gases​

Answers

Answer:

It is less dense than air so it will help the airship float, and it is not flammable so the airship is less likely to catch on fire. None of the other noble gases have similar or better reasons.

Explanation:

15) Circle one and tell whya. CH3COOH is a n) (acid, base, salt)b. NH4Cl is a(n) (acid, base, salt)c. KOH is a(n) (acid, base, salt)d. H3PO4 is a(n) (acid, base, salt)e. CaBr2 is a(n) (acid, base, salt)

Answers

The answers to the given questions are:

a. CH3COOH = acid
b. NH4Cl = salt
c. KOH = base
d. H3PO4 = acid
e. CaBr2 = salt

Reasons:

a. This compound is also known as acetic acid, the acid found in vinegar. It can be observed that the compound has a hydrogen ion which makes the compound acidic.

b. Ammonium chloride is a salt because it is the product of an acid (hydrochloric acid, HCl) and base (ammonium hydroxide, NH4OH)

c. Potassium hydroxide is a base because of the presence of OH ion

d. Phosphoric acid is a base because it has 3 hydrogen ions that contributes to its acidity

Answer:

C) CH3COOH Is the answer you are looking for

Explanation:

This one makes the most sense and the other ones don't fit in with the acids they aren't Acidic those are either bases or neutrals! :)

Hope this helps! :)