Main Street and Washington Avenue meet at a right angle. A large park begins at this corner. Joe's school lies at the opposite corner of the park. Usually Joe walks 1.2 miles along Main Street and then 0.9 miles up Washington Avenue to get to school. Today he walked a straight path across the park and returned home along the same path. What is the difference in distance between the two round trips?

Answers

Answer 1
Answer:

Joe walked a distance of 1.5 miles across the park to get to school.

And the difference in their 2 round trips is 1.2 miles.

What is Pythagoras' theorem?

Pythagoras' Theorem states that the square of the hypotenuse side of a right-angled triangle is equal to the sum of the squares of the other two sides.

We can use the Pythagorean theorem to find the distance that Joe walked today.

Let's call this distance d.

Since Joe walked a straight path across the park, the distance he covered can be represented by the hypotenuse of a right triangle, with Main Street and Washington Avenue as the legs.

Now,

d² = 1.2² + 0.9²

d² = 1.44 + 0.81

d² = 2.25

d = 1.5

Therefore, Joe walked a distance of 1.5 miles across the park to get to school.

To find the difference in distance between the two round trips, we can subtract the distance that Joe usually walks from the distance he walked today, and double the result, since he has to walk back home.

Hence,

2 × (-1.5 + 1.2 + 0.9) = 1.2 miles

Therefore, the required distance is 1.2 miles.

To learn more about the Pythagoras theorem;

brainly.com/question/343682

#SPJ3

Answer 2
Answer: Here is my work:
Distance is 1.2 miles
:-)

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Answers

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Answers

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Answers

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Answers

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Answers

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Answers

Answer:

4

Step-by-step explanation:

4-0.25*10+0.5*5=4-2.5+2.5=4

4-0.25g + 0.5h
g=10
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4 -2.5 +2.5

The answer is 4