MATHEMATICS HIGH SCHOOL

Which is the area of a circle with a radius of 5 units? (use 3.14 for )?

Answers

Answer 1

Answer:

Answer:

The area of circle is 78.5 units².

Step-by-step explanation:

Area of the circle is defined by the formula A = π r²

Here r = radius of the circle and value of π = 3.14

Now by putting these values in the formula we can get area of the circle.

A = (3.14) × 5²

A = 3.14 × 25

A = 78.5 units²

The area of circle is 78.5 units²

Answer 2

Answer: The area of a circle is A=πr².
Since π is about 3.14 we can substitute that into the equation.
So A=3.14×r²
We can substitute the given radius for r.
A= 3.14 × 5²
When a number is squared, or has the two over it, we multiply it by itself.
5 × 5= 25
A= 3.14 × 25
Simplify this and the area of the circle is about 78.5
A≈78.5

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Solve the formula C = rd for d.O A. de C
O
T
OB. d= C-1
O C. d=1
O D. d= TC

Answers

Answer:

C/R = D

Step-by-step explanation:

When you divide rd by r, then r is eliminated and divided into the C

hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.

Answers

Answer:

$2√(6)$

Step-by-step explanation:

Perimeter of equilateral triangle = 36 inches

Formula of perimeter of equilateral triangle = $3* side$

⇒ $36=3* side$

⇒ $(36)/(3) = side$

⇒ $12= side$

Thus each side of equilateral triangle is 12 inches

Formula of area of equilateral triangle = $(√(3))/(4) a^(2)$

Where a is the side .

So, area of the given equilateral triangle = $(√(3))/(4) * 12^(2)$

= $36√(3)$

Since hexagon can be divided into six small equilateral triangle .

So, area of each small equilateral triangle = $(36√(3))/(6)$

= $6√(3)$

So, The area of small equilateral triangle :

$(√(3))/(4)a^(2) =6√(3)$

Where a is the side of hexagon .

$(1)/(4)a^(2) =6$

$a^(2) =6* 4$

$a^(2) =24$

$a =√(24)$

$a =2√(6)$

Hence the length of a side of the regular hexagon is $2√(6)$

$Perimter\ of\ equilateral\ triangle\ =36\n a- \ side\ of\ triangle\n 36=3a\ |:3\n a=12\n\n Area\ of\ equilateral\ triangle:\n A=(a^2√(3))/(4)\n A=(12^2√(3))/(4)\n A=(144√(3))/(4)=36\sqrt3 \n\n Hegagon\ can\ be\ divided\ into\ 6\ equilateral\ small\ triangles.\nArea\ of\ one\ of\ them: A_s=(A)/(6)=(36\sqrt3)/(6)=6√(3)\n s-side\ of\ equilateral\ =\ side\ of\ small\ triangle\n A_s=(s^2√(3))/(4)=6√(3)\ |*4 \n s^2\sqrt3=24\sqrt3\ |\sqrt3\n s^2=24\n s=√(24)$ $√(24)=√(4*6)=2\sqrt6\n\n Side\ of\ hexagon\ equals\ 2\sqrt6\ inches$

Evaluate, 2 x {[5 x (60-14 divided by 7)] + 25} x 5=?

Answers

$2 * \left \{ [5 * (60-(14 )/(7) )] + 25 \right \} * 5=2 * \left \{ [5 * (60-2)] + 25 \right \} * 5= 2 * \left \{ (5 * 58) + 25 \right \} * 5=\n\n= 2 * \left \{ 290 + 25 \right \} * 5=2*315*5=3150$

Evaluate the expression 36y + 9 if y =1/6

Answers

36y + 9
=36 x 1/6+ 9
= 36/6 + 9
= 6 + 9
= 15

Two lines are perpendicular. The slope of one line is -2, What is the slope of the other line?A. 1/2

B. -1/2

C. -2

D. 2

Answers

perpendicular lines have negative reciprocal slopes. All that means is " flip " the slope and change the sign.
slope = -2, or -2/1....so flip the slope...-1/2...and change the sign...1/2.
so the perpendicular slope would be 1/2.

Please help out i’m stuck please and thank you

Answers

Answer: y = (4/3)x + 2

======================================================

Explanation:

The given equation is y = (-3/4)x - 2. Comparing it to y = mx+b, the slope is m = -3/4

Flip the fraction and the sign to go from -3/4 to 4/3. This is the perpendicular slope. Multiplying the two slopes gets (-3/4)*(4/3) = -1.

Rule: the original slope and perpendicular slope always multiply to -1, assuming neither line is vertical or horizontal.

We'll use the point (x,y) = (3,6) and the perpendicular slope m = 4/3 to find the y intercept b

y = mx+b

6 = (4/3)(3) + b

6 = 4+b

6-4 = b

2 = b

b = 2

The y = mx+b equation becomes y = (4/3)x + 2 which is the slope intercept form of the perpendicular line.

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Extra info:

If you want to convert to standard form Ax+By = C, then you could do the following steps

y = (4/3)x + 2

3y = 4x + 6 ... multiply everything by 3 to clear out the fraction

3y - 4x = 6

-4x + 3y = 6

4x - 3y = -6 ... multiplying both sides by -1; this is to make A > 0

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