The common factors of 28 and 40

Answers

Answer 1

Answer: The factors of 28 are 1, 2, 4, 7, 14, and 28.

The factors of 40 are 1, 2, 4, 5, 8, 10, 20, and 40.

The common factors are 1, 2, and 4.

Related Questions

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A flower shop sells tulips and roses. The price of each tulip is the same, and the price of each rose is the same. One customer bought 7 tulips and 9 roses for $25.90. Another customer bought 4 tulips and 8 roses for $19.80. How much will it cost a customer to buy 5 tulips and 6 roses?

The relationship between the number of 12$ DVDs you by and the total cost

Answers

Answer:

C = 12n

Step-by-step explanation:

Let C = the total cost

and n = the number of DVDs

Then

C = 12n

What is (-8)(-8)(-1)?

Answers

-64, using the negative times negative equals positive and negative times anything else = negative rule, you get -64

by multiplying -8 (-8) you get 64. then 64 (-1) equals -64

The sum of 5 consecutive odd integers is 2,555. What is the sum of the first, third, and last integer?

Answers

Answer:

The sum of the first, third, and last integer is 1533.

Step-by-step explanation:

Step 1: You need to create a equation first:

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

How did I make the equation?

If n is odd number, n + 2 must be the consecutive odd number

5 , 5 + 2 , 5 + 4 , 5 + 6 , 5 + 8

5, 7, 9, 11, 13 ALL CONSECUTIVE ODD NUMBERS

Step 2: Simplifying the equation

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

5n + 20 = 2555

Step 3: Solving the equation, with explanation

5n + 20 = 2555 Subtract 20 on both sides

5n = 2535 Isolate the variable by dividing 5 on both sides

n = 507

Step 4: Plug in the value

n + n + 2 + n + 4 + n + 6 + n + 8

507, 507 + 2 , 507 + 4 , 507 + 6 , 507 + 8

507, 509, 511, 513, 515

Step 5: Solve the sum of the first, third, and last integer

507 + 511 + 515 = 1533

Step 6: THE ANSWER

1533

Hope this helps!!!

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Solve the equations using the substitution method:
4x -2y =22
2x + 4y = 6

Answers

we have that
4x -2y =22------> clear variable y
2y=4x-22--------> y=4x/2-22/2---------> y=2x-11-----> equation 1
2x + 4y = 6------> equation 2

substitute equation 1 in equation 2
2x+4*[2x-11]=6-----> 2x+8x-44=6----> 10x=50------> x=5
then
y=2x-11----> y=2*5-11----> y=-1

Could use some help please

Answers

For the first scenario, you’re looking at a compound interest problem. You’re given all the information you need, so just input it into the compound interest equation.

A = P(1 + r/n)^nt

P is your principal, aka starting amount. That’s the 12000 people you start with.

R is your rate of interest, aka how much your principal is expanding by. That’s the 5% growth rate each year, or 0.05.

N is the number of times your principal grows each year. That’s only once here.

T is however long the change lasts. In this scenario, its from 2006 to 2020, so 14 years.

Input all this in and solve for A, which is your total amount.

A = 12,000(1 x 0.05/1)^(1 x 14) = 23,759.18

Since I doubt you can have 1/5 of a person, you round this down to 23,759, which is your answer.

I’d like to help with your second problem, but it’s cut off on the edge of the image, I can’t see all the numbers.

Chaleah deposited $900 in a new account that will earn 6% simple interest. After 2 years how much interest will she have earned?

Answers

she would earn an interest of $108

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In Smallville 2400 out of 20,000 workers are unemployed in big town 6750 out of 75,000 workers are unemployed which town has a larger unemployment problem why