both vacuums and mediums
mediums only
mediums only, mechanical waves always propagate through medium
where m is mass, c is the speed of the light, and E is the energy. In SI units, the units of speed are m/s. For the preceding equation to have consistent units (the same units on both sides of the equation), the units of E must be which of the following?
Answer:
Unit of energy is kg-m/s or Joules.
Explanation:
The mass- energy relationship in physics is given by :
Where
m is the mass of the object
c is the speed of light
The SI unit of m is kilogram while the SI unit of c is as same as speed of light i.e. m/s. So, the unit of energy is kg-m/s. It is also equivalent to Joules.
So, the SI unit of energy is kg-m/s or Joules. Hence, this is the required solution.
Directly proportional
The electric field strength at a distance of 0.020 m from a 12 µC point charge is approximately 2.69 x 10⁸ N/C.
The electric field strength (E) at a point near a point charge is given by the equation:
E = k Q / r²
where:
k is Coulomb's constant, equal to 8.99 x 10⁹ Nm²/C²
Q is the magnitude of the point charge in coulombs
r is the distance from the point charge
Substituting the given values:
Q = 12 x 10⁻⁶ C
r = 0.020 m
E = k Q / r²
E = 8.99 x 10⁹ Nm²/C² x 12 x 10⁻⁶ C / (0.020 m)²
E = 2.69 x 10⁸ N/C
So the electric field strength at a distance of 0.020 m from a 12 µC point charge is approximately 2.69 x 10⁸ N/C.
Learn more about the electric field strength here:
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Hi there!
40 N/m
We can use Hooke's Law:
F = kx or F = -kx
F = force (N)
k = Spring constant (N/m)
x = displacement (m)
We are given the force and displacement, so:
F/x = k
30/0.75 = 40 N/m
Both F's are forces, so µ must be unitless/dimensionless.
F[friction] = µ F[normal]
Or, more explicitly in terms of the units:
(Newtons) = (constant) (Newtons)