Two angles in a triangle add up to 135 degrees what is the size of the third angle?

Answers

Answer 1

Answer:
This question is checking to see if you remember what the three angles
of any triangle always add up to. Apparently you don't, or you would not
need to go out looking for somebody who does.

The three angles inside every triangle always add up to 180° .

If two of them add up to 135° , then that leaves

(180° - 135°) = 45° .

for the one remaining angle.

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Find all the real square roots of 0.0064

Answers

√64 = 8

64÷1000 = 0.0064

8÷1000=0.0008

√0.0064 = 0.0008

Please solve this -2x + 12y - 4

Answers

2 (2x - (2 - 2y + 3x) + 4y) =
2 (2x - 2 - 2y + 3x + 4y) =
2 (5x + 2y - 2) =
10x + 4y - 4
This was my solution.

Solve the equation for a: r=a+k/b a= ?

Answers

r = a + k/b

a = r - k/b

a = 1/b (r.b - k)

Which statements for 15.489 are true? Check all that are true. The digit 9 is in the tenths place. The digit 4 is in the tenths place. The digit 9 is in the thousandths place. The digit 8 is in the hundredths place. The digit 8 is in the thousandths place?

Answers

Digit 9 -1's place

Digit 4 - 100ths

Digit 8 - 10ths

Answer:

B. The digit 4 is in the tenths place

C. The digit 9 is in the thousandths place

D. The digit 8 is in the hundredths place

Step-by-step explanation:

A. The digit 9 is in the thousandths place

E. The digit 8 is in the hundredths place.

Hope it helped!

Assume all variables and groupings are nonzero real numbers.Write expressions with only positive exponents.

ab -4 c -3
the -4 and -3 are exponents.

Answers

$ab^(-4)c^(-3)=\n (a)/(b^4c^3)$

Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right endpoint of each interval. Give three decimal places in your answer.

Answers

Hello,

Reminders:
$\sum_(i=1)^(n) i= (n(n+1))/(2)$
$\sum_(i=1)^(n) i^2= (n(n+1))/(2)$
$\sum_(i=1)^(n) i^3= (n^2(n+1)^2)/(4)$

$n=6\n x_(0)=0\n x_(n)=3\n \Delta= (x_n-x_0)/(n)=0.5\n$
$x_(i) =0+\Delta*i= (i)/(2)$

$\sum_(i=1)^(n)\ \Delta*f(x_(i))=\sum_(i=1)^(6)\ (i^3/8-6i)/(2)$
$$= (1)/(2)\sum_(i=1)^(6) ((i^3)/(8) -6i)=(1)/(16)*((6*7)^2)/(4)- (9*7)/(2)= -3.9575$

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