Earth's tectonic activity is a significant factor that made life on Earth possible because the movement of Earth's crustal plates affects _____.

Answers

Answer 1
Answer: Earth's tectonic activity is a significant factor that made life on Earth possible because the movement of Earth's crustal plates affects volcanic activity.

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The flywheel of a steam engine runs with a constant angular velocity of 140 rev/min. When steam is shut off, the friction of the bearings and of the air stops the wheel in 1.9 h. (a) What is the constant angular acceleration, in revolutions per minute-squared, of the wheel during the slowdown? (b) How many revolutions does the wheel make before stopping? (c) At the instant the flywheel is turning at 70.0 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 40 cm from the axis of rotation? (d) What is the magnitude of the net linear acceleration of the particle in (c)?

Answers

Answer:

A) α = -1.228 rev/min²

B) 7980 revolutions

C) α_t = -8.57 x 10^(-4) m/s²

D) α = 21.5 m/s²

Explanation:

A) Using first equation of motion, we have;

ω = ω_o + αt

Where,

ω_o is initial angular velocity

α is angular acceleration

t is time the flywheel take to slow down to rest.

We are given, ω_o = 140 rev/min ; t = 1.9 hours = 1.9 x 60 seconds = 114 s ; ω = 0 rev/min

Thus,

0 = 140 + 114α

α = -140/114

α = -1.228 rev/min²

B) the number of revolutions would be given by the equation of motion;

S = (ω_o)t + (1/2)αt²

S = 140(114) - (1/2)(1.228)(114)²

S ≈ 7980 revolutions

C) we want to find tangential component of the velocity with r = 40cm = 0.4m

We will need to convert the angular acceleration to rad/s²

Thus,

α = -1.228 x (2π/60²) = - 0.0021433 rad/s²

Now, formula for tangential acceleration is;

α_t = α x r

α_t = - 0.0021433 x 0.4

α_t = -8.57 x 10^(-4) m/s²

D) we are told that the angular velocity is now 70 rev/min.

Let's convert it to rad/s;

ω = 70 x (2π/60) = 7.33 rad/s

So, radial angular acceleration is;

α_r = ω²r = 7.33² x 0.4

α_r = 21.49 m/s²

Thus, magnitude of total linear acceleration is;

α = √((α_t)² + (α_r)²)

α = √((-8.57 x 10^(-4))² + (21.49)²)

α = √461.82

α = 21.5 m/s²

An object is moving to the right, and experiencing a net force that is directed to the right. The magnitude of the force is decreasing with time. The speed of the object is:A. increasingB. constant in timeC. decreasing

Answers

Answer:

The speed of the object is increasing.

F = M a       as long as the magnitude of the acceleration is acting towards the right there will be an acceleration towards the right

All contraceptives prevent STIs true or false

Answers

False. Not all contraceptives prevent STIs.

Contraceptives are items used or taken to prevent conception. These are birth control pill, patch, ring, IUD, birth control shots, and condoms. Among these contraceptives, condoms are the only type of birth control that prevents STIs or Sexually Transmitted Infections.

All contraceptives prevent STIs is False because not all them are used in STI prevention.

What is contraceptives about?

Not all contraceptives prevent sexually transmitted infections (STIs). Only condoms, dental dams, and some internal condoms, such as the female condom, can help prevent the transmission of STIs.

Other forms of contraception, such as birth control pills, the patch, the ring, and the shot, do not protect against STIs. This is because they work by preventing ovulation or by thickening the cervical mucus, which makes it more difficult for spermto reach the egg. They do not prevent the transmission of STIs because they do not block the exchange of bodily fluids, which is how STIs are spread.

So, the answer is false.

Find out more on contraceptives here: brainly.com/question/2296833

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Before starting this problem, review Conceptual Example 3 in your text. Suppose that the hail described there comes straight down at a mass rate of m/?t = 0.030 kg/s and an initial velocity of v0 = -15 m/s and strikes the roof perpendicularly. Suppose that the hail bounces off the roof of the car with a velocity of +15 m/s. Ignoring the weight of the hailstones, calculated the force exerted by the hail on the roof. __________N

Answers

Answer:

0.9 N

Explanation:

The force exerted on an object is related to its change in momentum by:

F=(\Delta p)/(\Delta t)

where

F is the force exerted

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be rewritten as

\Delta p = m(v-u)

where

m is the mass

u is the initial velocity

v is the final velocity

So the formula can be rewritten as

F=(m(v-u))/(\Delta t)

In this problem we have:

(m)/(\Delta t)=0.030 kg/s is the mass rate

u=-15 m/s is the initial velocity

v=+15 m/s is the final velocity

Therefore, the force exerted by the hail on the roof is:

F=(0.030)(+15-(-15))=0.9 N

In scientific terms, how is power related to work? A.Power is the ability to do work.


B.Power is the force of work over a certain distance.


C.Power is the rate at which work is accomplished.


D.Power is the energy supplied in a force.

Answers

The answer is c. Hope this helps :)

Energy is measured in Joules (J). Which other quantity is measured in Joules?a. work
b. force
c. power
d. acceleration

Answers

I think the answer is B so force

Answer:

C. power

Explanation: