The main difference between speed and velocity involves A. direction.
B. weight.
C. gravity.
D. distance.

Answers

Answer 1

Answer: A. Direction

Speed is just distance divided by time, but velocity is displacement divided by time and displacement has direction. Speed will always be positive, but velocity can be either positive or negative.

Answer 2

Answer:

The Correct answer to this question for Penn Foster Students is: Direction

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A spherical electron cloud surrounding an atomic nucleus would best represent
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A deep draught vessel sailing in a very narrow channel can develop a sudden sheer as it slows down. What could be the cause of this?
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Which concept represents most encompassing aspect of our lives

Answers

the most ecompassing aspect of our lifes is emotional health

The direction of swing of a Foucault pendulum appears to change due to Earth’s

Answers

French Physicist Leon Foucault introduced his pendulum in 1851.
By that time, it was generally accepted that the Earth rotates, but
Foucault's pendulum was the first simple demonstration that made
the Earth's rotation easy to prove.

Which is more 3 tons or 6001 pounds

Answers

3 tonnes

The answer is 3 tonnes, because 3 tonnes equal 6613.87 pounds, which is higher than 6001.

I hope this helps! I would love it if you could help me answer my question too!

Final answer:

6001 pounds is slightly more than 3 tons. This is because, in the comparison scale, 1 ton is equal to 2000 pounds. So, 3 tons equals 6000 pounds.

Explanation:

The student is asking which is more, 3 tons or 6001 pounds. To determine this, we need to understand the relationship between tons and pounds. We know that 1 ton is equivalent to 2000 pounds. So, 3 tons would be equivalent to 3*2000 = 6000 pounds.

Hence, comparing 6001 pounds with 3 tons, or effectively 6000 pounds, 6001 pounds is slightly more than 3 tons.

Learn more about Weight comparison here:

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Magnetic fields are produced by particles that are(1) moving and charged
(2) moving and neutral
(3) stationary and charged
(4) stationary and neutral

Answers

Magnetic fields are produced by particles that are moving and charged.

Answer:

the correct answer is 1 moving and charged.

Explanation:

Magnetic fields are produced by moving electric charges. Everything is made up of atoms, and each atom has a nucleus made of neutrons and protons with electrons that orbit around the nucleus.

What kind of image is formed by an object that is placed beyond the center of curvature on the principal axis of a concave mirror?A.
real, inverted, the same size as the object, and at the same distance as the object
B.
real, inverted, larger than the object, and farther from the mirror than the object
C.
virtual, upright, left-right reversal, the same size as the object, and at the same distance as the object
D.
real, inverted, smaller than the object, and closer to the mirror than the object
E.
virtual, upright, larger than the object, and farther from the mirror than the object

Answers

Answer:D.

Real, inverted, smaller than the object, and closer to the mirror than the object

Explanation: Real images will be inverted. As it is beyond the centre of curvature it is also beyond 2F which means that the image is inside the centre of curvature ( between F and 2F from the mirror ) As the image is closer to the mirror than the object it must be diminished in size

Heat of Fusion How much thermal energy is needed change 50.0 g of ice at -20.0°C to water at 10.0°C?

Answers

We should divide the problem into 3 separate processes.

1) Bring the temperature of the ice from $-20.0^(\circ)C$ to its melting point ( $0^(\circ)C$ ): the amount of heat needed in this process is
$Q_1=mC_s \Delta T$
where
$m=50.0 g$ is the mass of the ice
$C_s = 2.108 J/g^(\circ)C$ is the specific heat capacity of ice
$\Delta T=0^(\circ)C-(-20^(\circ)C)=20^(\circ)C$ is the increase of temperature

Plugging numbers into the equation, we find
$Q_1 = (50.0 g)(2.108 J/g^(\circ)C)(20^(\circ)C)=2108 J$

2) Fusion of ice
When the ice is at melting point, we need to add a certain amount of heat in order to melt it, and this amount of it is given by:
$Q_2 = mL_f$
where
$m=50.0 g$ is the mass of ice
$L_f = 334 J/g$ is the latent heat of fusion of ice

Plugging numbers into the equation, we find
$Q_2 = mL_f = (50.0g)(334 J/g)=16700 J$
During this phase transition, the temperature of the ice/water does not change.

3) Bring the temperature of the water from $0^(\circ)C$ to $10^(\circ)C$

The amount of heat needed for this process is
$Q_3 = mC_s \Delta T$
where
$m=50.0 g$ is the mass of water
$C_s = 4.187 J/g^(\circ)C$ is the specific heat capacity of water
$\Delta T=10^(\circ)C-0^(\circ)C=10^(\circ)C$ is the increase of temperature

Plugging numbers into the equation, we find
$Q_3 = (50.0 g)(4.187 J/g^(\circ)C)(10.0^(\circ)C)=2094 J$

--> therefore, the total energy needed for the whole process is:
$Q=Q_1+Q_2+Q_3=2108 J+16700 J+2094 J=20902 J=20.9 kJ$

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