What is 3476 divided by 6

Answers

Answer 1

Answer:

579.3 repeating

that's the answer you just divide that's all

Answer 2

Answer: My calculator says 579.333333333 so I am just guessing it would be 579? But I would recommend getting some more answers before you go with mine.

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A number cube is rolled and a coin is flipped. Possible outcomes How many possible outcomes are there? What are the missing table values?

Answers

A number cube has 6 faces and a coin has 2 faces.
Number of possible outcomes is 6 x 2 = 12

How many possible outcomes are there?

[12]

What are the missing table values?

a = H2

b = T6

What is the answer for 3912.99/15.9

Answers

The question asks the answer that comes out from the division of 3912.99 by 15.9. Both the numbers are in decimal form, so the division will be easy.
3912.99/15.9
= (391299 * 10)/(159 * 100)
= (391299)/(1590)
= 246.10
So the answer that comes out from the division of the two numbers given in the question is 246.10. I hope i have described the full process and it has helped you to understand the way these kind of problems need to be tackled.

The answer to your question is 246.1

Suppose you had $6.00 to buy bananas and apples. Bananas cost $0.49 per pound andapples cost $0.34 per pound. Write a linear equation that represents the different
amounts of fruit you could buy. If you buy 10 pounds of bananas, how many pounds of
apples would it be possible to buy?

Answers

X= pounds of apples
0.34x+0.49(10)=6
0.34x+4.9=6
0.34x=1.1
X=3.23

Answer: it is possible to buy 3 pounds of apples

Final answer:

A linear equation is written to represent the cost of buying different amounts of fruit. If one buys 10 pounds of bananas, they could also afford to buy approximately 3.24 pounds of apples.

Explanation:

The esential first step here is to write a linear equation that can represent the different amounts of fruits you could buy. Let's denote the pounds of bananas and apples as b and a respectively. The cost per pound of bananas and apples can be represented as 0.49b and 0.34a respectively. The total cost is $6.00. Hence the equation becomes:

0.49b + 0.34a = 6.00

With this equation, we can calculate the possible pounds of apples you could buy with 10 pounds of bananas. Substitute b = 10 into the equation:

0.49(10) + 0.34a = 6.00

4.9 + 0.34a = 6.00

By subtracting 4.9 from both sides of the equation and then dividing by 0.34, we can solve for a:

a ≈ 3.24

Therefore, with 10 pounds of bananas, it would be possible to buy approximately 3.24 pounds of apples with the remaining amount of money.