Answer:
3 in the tens place
5x-2y=6
thx to the ppl who help
Arithmetic Sequence
The value of the 93th term of this arithmetic series is -925
Step-by-step explanation:
The first term of the arithmetic term is a = -5
And the common difference is d = a2-a1 = -15 - ( - 5) = -10
So the 93th term if this arithmetic progression is given by
an = a + (n-1) × d
where an is the nth term of the arithmetic progression
so in order to calculate the 93rd term (a93), the value of n = 93
so a93 = -5 + (93-1) × (-10)
a93 = -5 + (-920)
a93 = -925
Hence the value of the 93th term of this arithmetic series is -925
The 93rd term of the arithmetic sequence is -925.
Here, we have to find the nth term of an arithmetic sequence, you can use the formula:
nth term = first term + (n - 1) * common difference
where:
first term = the first term of the sequence
common difference = the difference between consecutive terms
n = the term number you want to find
In this case, we have the arithmetic sequence:
-5, -15, -25, ...
Here, the first term (a) is -5,
and the common difference (d) is -15 - (-5) = -10.
Now, we want to find the 93rd term (n = 93) of this sequence.
nth term = -5 + (93 - 1) * (-10)
nth term = -5 + 92 * (-10)
nth term = -5 + (-920)
nth term = -925
So, the 93rd term of the arithmetic sequence is -925.
To lean more on Arithmetic progression click:
#SPJ3