Almira earns 50$ an hour. how much does she earn in 6 hours

Answers

Answer 1

Answer: If it is $50 per hour, and she works for 6 hours you time 50 by 6 which equals 300

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A piece of ribbon that is 8 and 1/3 yards long will be cut into 5 equal pieces to make bows. How much ribbon will be used foe each bow?

Answers

Answer:

yes

Step-by-step explanation:

Answer: 1 2/3 yards for each bow

Step-by-step explanation:

8 1/3 divided by 5 = 25/3 * 1/5 = 5/3

A conditional relative frequency table is generated by row from a set of data. The conditional relative frequencies of the two categorical variables are then compared.If the relative frequencies are 0.48 and 0.52, which conclusion is most likely supported by the data?

A.) There is likely an association between the categorical variables because the relative frequencies are similar in value.

B.) An association cannot be determined between the categorical variables because the relative frequencies are similar in value.

C.) An association cannot be determined between the categorical variables because the relative frequencies are not similar in value.

D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50.

Answers

If the relative frequencies are 0.48 and 0.52, we conclude that: A. There is an association between the categorical variables because they are similar in value.

What is a two-way frequency table?

A two-way frequency table can be defined as a type of table that is used for the graphical representation of frequencies (relative frequencies) that are associated with two (2) categorical variables.

This ultimately implies that, a two-way frequency table can be used to show, analyze, and examine the relationships that exists between two (2) categorical variables.

In conclusion, we can conclude that there is an association between the categorical variables because the relative frequencies have the same (similar) value, especially if theyare 0.48 and 0.52.

Read more on frequency here: brainly.com/question/20744563

Answer: A

Step-by-step explanation:

Did it on edge

Johnathon has 3 balls and his dog takes one and rips it in half, how many balls does he have now?

Answers

He has three balls. Two which are complete and one that has two halves. Or he only has 2 and one that he can't play with anymore

Please help me with this math question?? :)The measure of each exterior angle of a regular octogon is _____ the measure of each exterior agle of a regular hexagon.

A. Greater than
B. Less than
C. Equal to

Answers

$\bf \textit{exterior angle of a regular polygon}\n\n\n\theta=\cfrac{360}{n}\qquad \begin{cases}\theta=\textit{the angle in degrees}\nn=\textit{number of sides}\end{cases}$

now, an OCTAgon, has OCTA=8, sides
an HEXAgon, has HEXA=6, sides

check what their external angles are, and compare :)

Marley drives to work every day and passes two independently operated traffic lights. The probability that both lights are red is 0.35. The probability that the first light is red is 0.48. What is the probability that the second light is red, given that the first light is red?a)0.13
b)0.35
c)0.48
d)0.73

Answers

Probability1 *Probability2
0.35 = 0.48 * P2

0.35/0.48 = P2
P2 = 0.7291666...,
d)0.73 is correct

particular reactant decomposes with a half?life of 147 s when its initial concentration is 0.294 m. the same reactant decomposes with a half?life of 215 s when its initial concentration is 0.201 m.

Answers

Answer:

The first reactant takes approximately 147 seconds to reach half its initial concentration, while the second reactant takes approximately 214.5 seconds for the same reduction, based on their half-lives and initial concentrations.

Step-by-step explanation:

The rate constant (k) for a first-order reaction can be calculated using the formula:

k = (0.693) / t_half

For the first set of data:

k₁ = (0.693) / 147 s ≈ 0.00472 s⁻¹

For the second set of data:

k₂ = (0.693) / 215 s ≈ 0.00322 s⁻¹

Now, you can use these rate constants to calculate the time it takes for each reactant to reach a certain concentration. For example, if you want to find the time it takes for the first reactant (initial concentration = 0.294 M) to reduce to 0.147 M (half its initial concentration), you can use the following equation for a first-order reaction:

ln(C_t / C₀) = -kt

Where:

C_t = concentration at time t

C₀ = initial concentration

k = rate constant

t = time

For the first reactant:

ln(0.147 / 0.294) = -0.00472t

Solving for t:

t ≈ 147 seconds

For the second reactant (initial concentration = 0.201 M) to reduce to 0.1005 M (half its initial concentration):

ln(0.1005 / 0.201) = -0.00322t

Solving for t:

t ≈ 214.5 seconds

So, it takes approximately 147 seconds for the first reactant to reach half its initial concentration, and approximately 214.5 seconds for the second reactant to do the same, based on their respective half-lives and initial concentrations.

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