C2H6O + O2
ethanol oxygen gas --------------------------------------------------
What elements will be present in the substances that are created when ethanol burns?
Answer:
Carbon, hydrogen, and oxygen only will be present in the substances that are created when ethanol burns.
Explanation:
Combustion means the process by which the burning of any substance, whether gaseous, liquid or solid, occurs.
Combustion reactions are reactions where oxygen intervenes as a reagent. Oxygen has the ability to combine with various elements to produce oxides, where then oxidation is the combination of oxygen with another substance. There are oxidations that are extremely slow, but when oxidation is rapid it is called combustion.
When a substance containing carbon and hydrogen (a hydrocarbon) undergoes complete combustion, or burning, oxygen is consumed and carbon dioxide is produced, and water.
Then the reaction is:
C₂H₆O + O₂ ⇒ CO₂ + H₂O
The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.
Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts .
The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.
And by multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.
So, considering the above, the balanced chemical equation is:
2 C₂H₆O + 6 O₂ ⇒ 6 CO₂ + 6 H₂O
In the previous combustion reaction you can see that:
You can see that in a chemical reaction the elements in the reagents must be the same elements present in the products.
So, carbon, hydrogen, and oxygen only will be present in the substances that are created when ethanol burns.
electron
proton
Answer:
neutrons = 0
protons = +
electrons = -
Hydrogen: 6.478%
Carbon: 42.106
(C*12)+(H*22011)=505.272+142587.258=143092.53
A.
These are the physical properties of water.
B.
These are the chemical properties of water.
C.
These are the physical changes water undergoes.
D.
These are the chemical changes water undergoes.
E.
These are the molecular changes water undergoes.
IE1(Rb) = 397.5
BE(Cl2) = 226
deltaHf(RbCl) = -431
Electron Affinity Cl = -332
a. -53.7
b. +53.7
C. -695
d. -808
e. +808
Answer:
Option C
Explanation:
The chemical reactions which are involved while solving this problem is there in the file attached and each chemical reaction is represented by a certain equation number
Lattice energy for rubidium chloride ( RbCl) is represented by the equation 6
Equation 1 represents the change in enthalpy for formation of RbCl
Equation 2 represents the sublimation reaction of rubidium
Equation 3 represents the ionization enthalpy of rubidium
Equation 4 represents the enthalpy of atomization of chlorine which means it describes the bond enthalpy of Cl2 molecule
Equation 5 represents the electron affinity of chlorine
To find the lattice energy for RbCl we have to use all the equations from 1 to 5 so that at last we get the equation 6
We have to perform operations such as
Equation 1 - equation 2 - equation 3 - equation 4 - equation 5
By performing these operations the intermediate compounds gets cancelled and at last we get equation 6
So Equation 1 ≡ ΔH = -431 kJ/mol
Equation 2 ≡ Rb(s) ---> Rb(g) = 85.8 kJ/mol
Equation 3 ≡ IE1(Rb) = 397.5 kJ/mol
Equation 4 ≡ BE(Cl2) = 226 kJ/mol
Equation 5 ≡ Electron Affinity Cl = -332 kJ/mol
Value corresponding to the equation 6 will be the value of lattice energy of RbCl and the value is -695·3 kJ/mol
∴ Lattice energy for rubidium chloride is approximately -695 kJ/mol
The lattice energy for rubidium chloride (RbCl) is calculated by substituting the given values into the equation derived from Hess's Law. The calculated lattice energy is found to be -695 kJ/mol.
In this question, you are asked to select the lattice energy for rubidium chloride (RbCl). The lattice energy can be calculated using various given energies including enthalpy of formation (ΔHf), electron affinity (Cl), enthalpy of sublimation, ionization energy, and bond dissociation energy. Using Hess's Law, this can be summed up as:
ΔHf(RbCl) = [Sublimation Energy (Rb) + Ionization Energy (Rb) + 0.5 × Bond Energy (Cl₂) + Electron Affinity (Cl)] - Lattice Energy (RbCl)
By rearranging this formula, we find that the Lattice Energy (RbCl) = [Sublimation Energy (Rb) + Ionization Energy (Rb) + 0.5 × Bond Energy (Cl₂) + Electron Affinity (Cl)] - ΔHf(RbCl). Substituting in the given values, we find the lattice energy to be -695 kJ/mol. Therefore, the correct option is C. -695.
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