a student measures the mass of an 8cm3 block of brown sugar to be 32g.what is the density of the brown sugar ?

Answers

Answer 1

Answer: D= Densitym= massV= VolumeD=m÷V= 8÷32D= 1/4

Answer 2

Answer: D = m/v
D = 32g/8cm^3
D = 4g/cm^3

I am write the other answer is wrong. She got her numbers mixed. Mass is calculated using grams and volume is calculated using cm cubed.

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The Moore family is adding a brick patio to their back yard. Mr. Moore is determining howmany square bricks he needs for his rectangular patio, as well as the cost. His sketch isshown below and is not drawn to scale. Use the formula A=bh to help answer the questionsbelow.
A calculator was purchased for $29. The wholesale cost was $20. What was the percent markup?
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From a point on a circle, two perpendicular chords are drawn. One is 6 cm from the center and the other one is 3 cm from the center. Find the lengths of these chords.

Answers

The chord 3cm away is 12cm and chord 6cm away is 6cm.
The two perpendicular chords will create a rectangle with the center. each side will be half of the parallel sides length.

Draw quick pictures and write to explain how to break apart addends to find the sum of 324 + 231

Answers

Answer: The explanation of the given addition is mentioned below.

Step-by-step explanation:

Since Here we have numbers 324 and 231.

So if we want to add these two numbers then at first we should add 4 and 1, That is 4+1= 5, which is the once place digit of our answer.

Now we should add 2 and 3 , that is , 2+3 =5 which is the tense place digit of our answer.

Finally we should add 3 and 2 the result is 3+2= 5 , which is the hundreds place digit of our answer.

Thus the complete result is 555.

Organize the following polynomial expressions from least to greatest based on their degree:6x2
18x3 + 5ab - 6y
8a - 5
4x3y + 3x2 - xy - 4
III, I, IV, II

IV, II, I, III

III, I, II, IV

IV, I, II, III

Answers

The correct answer is
III, I, II, IV
8a - 5
6x2
18x3 + 5ab - 6y
4x3y + 3x2 - xy - 4

Answer:

The correct answer is C)

III, I, II, IV

8a - 5

6x2

18x3 + 5ab - 6y

4x3y + 3x2 - xy - 4

Step-by-step explanation:

An object is traveling around a circle with a radius of 10 cm. If in 20 seconds a central angle of 1/3 radian is swept out, what is the linear speed of the object?

Answers

The linear speed of the object is $(1)/(6)$

The Radius, r = 10 cm
The Fraction of Radius swept out = $(1)/(3)$
The distance = $10 / (1)/(3)$
The distance covered = $(10)/(3)$

The linear speed :

Radius swept out ÷ time taken
$(10)/(3) * (1)/(20) = (1)/(6)$

The linear speed of the object is $(1)/(6)$

Learn more : brainly.com/question/15154430?referrer=searchResults

Firstly, we will find the distance covered by the object in the 20 seconds:

$\text{angle}(in~radians)=\frac{\text{arch}}{\text{radius}}\Longrightarrow (1)/(3)=(d)/(10~cm)\iff d=(10)/(3)~cm$

We must know that $v=(d)/(\Delta t)$ . So:

$v=(d)/(\Delta t)\Longrightarrow v=((10)/(3)~cm)/(20~s)\iff \boxed{v=(1)/(6)~cm/s}$

In a sale, there is 50% off all prices. A chair costs £17.50 in the sale. How much was it before the sale?

Answers

do 17.50 * 2 and youll get the answer so 17.50 * 2 is 35

£17.50 is 50% of what number
Now the same in math:
£17.50 = .50 x n pr £17.50 = .5n
Divide both sides by .5
n= £ 35

WILL GIVE BRAINLIESTHannah and Han are each trying to solve the equation x² – 8x + 26 = 0. They know that
x = -1 are i& - i, but they are not sure how to use this information to solve for x in their
equation.
Part 1- Here is Hannah's work:
x? - 8x + 26 = 0
X? – 8x = -26
Show Hannah how
to finish her work using completing the square and complex numbers.
Part 2- Han decides to solve the equation using the quadratic
formula. Here is the beginning of his
work
-b+V62-4ac
-(-8)+7-8)2–401|(26)
Finish using the quadratic formula. Simplify the final answer as much as possible.

Answers

The solutions are:-

$x=4+√(10i)\n\nx=4-√(10i)$

What is the equation?

The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Here given equation is

$x^2- 8x + 26 = 0\n\nx^2-8x=-26\n\n(x-4)^2=-10\n\n$

$(x-4)=$ ± $√(-10)$

$x=√(10)i+4\n\nx=-√(10)i+4$

So,

$x=(-b+-√(b^2-4ac))/(2a)\n\nx=(8+-√((-8)^2-4(1)(26)))/(2(1))\n\nx=(8+-√((-8)^2-4(1)(26)))/(2(1))\n\nx=(8+-√(64-104))/(2)\n\nx=(8+-2√(10i))/(2)\n\nx=(2(4+-√(10i)))/(2)\n\nx=4+√(10i)\n\nx=4-√(10i)$