Answer:
Siis the answer I hope this help
b. Calculate the molarity of the solution.
c. Calculate the mole fraction of the salt in the solution.
The molarity of the solution is 5.018 mol/L and molality of the solution 5.9846 mol/kg.
Assume 100 g of solution the salt concentration- 35 % and water will be 65 %.
So,
mass of salt = 35 g
mass of water = 65 g
Number of moles,
So,
moles of salt = 35 g / 90 (g/mol) = 0.389 mole
moles of water = 65 / 18 = 3.6111 mole
Volume of solution,
volume = 100 g / ( 1.29 g/ml)
volume of solution = 77.52 ml = 0.07752 L
a)
molality = 0.389 mol / 0.065 kg
molality = 5.9846 mol/kg
b)
molarity = moles of salt / volume of solution (L)
molarity = 0.389 mol / 0.07752 L
molarity = 5.018 mol/L
c)
mole fraction of salt = moles of salt / total moles
mole fraction of salt = 0.389 mol / ( 0.389 + 3.6111)
mole fraction of salt = 0.09725
To know more about Molarity,
Answer:
a) 5.9846 mol/kg
b) 5.018 mol/L
c)0.09725
Explanation:
consider 100 g of solution
now
since the salt is 35 % , water will be 65 %
now
mass of salt = 35 g
mass of water = 65 g
we know that
moles = mass / molar mass
so
moles of salt = 35 g / 90 (g/mol) = 0.389 mol
moles of water = 65 / 18 = 3.6111 mol
now
volume of solution = mass of solution / density of solution
volume of solution = 100 g / ( 1.29 g/ml)
volume of solution = 77.52 ml
volume of solution = 0.07752 L
a)molality = moles of salt / mass of water (kg)
molality = 0.389 mol / 0.065 kg
molality = 5.9846 mol/kg
b)
molarity = moles of salt / volume of solution (L)
molarity = 0.389 mol / 0.07752 L
molarity = 5.018 mol/L
c)
now
total moles in the solution = moles of salt + moles of water
total moles in the solution = 0.389 + 3.6111
total moles in the solution = 4 mol
now
mole fraction of salt = moles of salt / total moles
mole fraction of salt = 0.389 mol / 4 mol
mole fraction of salt = 0.09725
1. Will contain the same number of molecules
2. Will contain the same number of atoms
3. Will occupy the same volume
4. Will have the same g.f.w
Answer: The correct answer is Option 1 and Option 3.
Explanation:
We are given:
0.25 moles of
STP conditions states that 1 mole of a gas occupies 22.4 L of volume.
The volume occupied by all the gases at STP will be
According to mole concept: 1 mole of a compound contains number of molecules or 1 mole of an element contains
number of atoms.
We know that the given gases are compounds. Thus, all the three gases will have number of molecules.
Hence, the correct answer is Option 1 and Option 3.
Answer : The number of moles of is, 0.1 moles
Solution : Given,
Mass of = 6.2 g
Molar mass of = 62 g/mole
Now we have to calculate the moles of .
Therefore, the number of moles of present in 6.2 g is, 0.1 moles
no mass
large mass
high penetrating power
Answer: A) Some shielding required
Explanation:
Simpler for the E2020 Kids now enjoy