In which of the following situations would the least work have been done?A. A 100-N force lifts an object 3 m.
B. A 250-N force moves an object 1 m.
C. A 25-N force moves an object 8 m.
D. A 600-N force is applied to an object and moves it 0 m.

Answers

Answer 1
Answer:
Work = (magnitude of the force) x (distance in the direction of the force)

A 100-N force lifts an object 3 m.                ==>  (100 x 3) = 300 joules

B. A 250-N force moves an object 1 m.      ==>  (250 x 1) = 250 joules

C. A 25-N force moves an object 8 m.        ==>  (25 x 8)  =  200 joules

D. A 600-N force is applied to an object
    and moves it 0 m.                                   ==>  (600 x 0) = no work
                                                                           Winner ! Least work.


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Although the Bohr atomic model is helpful in counting electrons in their orbitals, why is this model inaccurate in terms of the actual location and movement of electrons around an atom’s nucleus?

Answers

Because real electrons are in an electron cloud, not layers

A road with a positive cross slope is highest __________.

Answers

A road with a positive cross slope is highest in the center of the road.

The roads with Cross slopes are formed to provide the drainage system so that water will run off from the surface. Due to this no water stands on the roads, especially when there is heavy rain it is very useful. It is a very important safety factor.

2 examples of all 7 wave behaviors

Answers

Answer:

radio waves

microwaves

All waves behave in certain characteristic ways. They can undergo refraction, reflection, interference and diffraction.

Compare the time taken by the RC car to cover the same distance. Do some go faster or slower?

Answers

There isn;t enough given values to define and determine what is asked. But since
distance = speed / time, time = distance / speed


Calculate the acceleration of a boat that has been cruising at 15 m/s but speeds up to 45 m/s in about 6 seconds. Don’t forget your units, m/s2. In order to calculate the acceleration of the boat we first have to identify the suited formula for acceleration in this scenario. 


Hence, a = vf – vi / t. Vi = 15 m/s Vf = 45 m/s T = 6 seconds   

Solution: 
A = 45 m/s – 15m/s / 6s 
A = 5m/s^2

The shorter the time required to cover the same distance, the greater the speed of the RC car.

Further explanation

Acceleration is rate of change of velocity.

\large {\boxed {a = (v - u)/(t) } }

\large {\boxed {d = (v + u)/(2)~t } }

a = acceleration (m / s²)v = final velocity (m / s)

u = initial velocity (m / s)

t = time taken (s)

d = distance (m)

Let us now tackle the problem!

The formula for finding speed is:

\large {\boxed {v = (s)/(t)} }

v = velocity (m/s)

s = distance (m)

t = time taken (s)

From the formula above, it is clear that speed is inversely proportional to travel time. The shorter the time required to cover the same distance, the greater the speed of the RC car.

For example, let's look at the data in the table in the attachment. RC Car B has the greatest speed

Learn more

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

An electromagnetic wave traveling through a vacuum has a wavelength of .15 meter. What is the period of this electromagnetic wave?

Answers

Tools we'll need:
Speed of EM wave in vacuum = 3 x 10⁸ meters per second.
Frequency = (speed) / (wavelength)
Period = 1/frequency

Period = (wavelength) / (speed) = (0.15) / (3 x 10⁸) = 0.5 nanosecond

( "nano..." = 10⁻⁹ )




What is the momentum of a 75.0-kilogram defensive back chasing the fullback at a velocity of 5.00 m/sec.

Answers

Answer : The momentum is, 357 kg.m/s

Explanation :

Momentum : It is defined as the motion of a moving body. Or it is defined as the product of mass of velocity of an object.

Formula of momentum is:

p=mv

where,  

p = momentum

m = mass  = 75.0 kg

v = velocity  = 5.00 m/s

Now put all the given values in the above formula, we get:

p=75.00kg* (5.00m/s)=357kg.m/s

Therefore. the momentum is, 357 kg.m/s


75 kg × 5 m/sec = 375 kgm/s

Hope this helps :)