In spite of the of his presentation, manypeople were with the speaker’s concepts
and ideas.
(A) interest…enthralled
(B) power…taken
(C) intensity…shocked
(D) greatness…gratified
(E) strength…bored

Answers

Answer 1
Answer: E strength/bored

In spite of the STRENGTH of his presentation, many
people were BORED with the speaker’s concepts
and ideas.



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$98 catered dinner; 18% gratuity cost to the nearest cent

What is the value of i^235?

Answers

Answer:

-i

Step-by-step explanation:

i²³⁵ = i²³² × i³

= (i⁴)⁵⁸ × -i

= -i

Which want is right in number 4 and 5

Answers

4.) C.

Your suppose to round to the hundredth. 

5.) D. 

Your suppose to round to the hundredths. 

( Every time for price always round to the nearest hundredths)
 


Solve the following equation then place the correct number in the box provided 3(2x+5)> 2(x+6)

Answers

The answer is actually x ≥ -3/4

6x+15>2x+12. 4x>-3. x>-3/4

What is 44,500 increase by 4%

Answers

1,780
44,500 times .04 (4% as a decimal)
equals 1,780

A magazine printed photos of three celebrities along with three photos of the celebrities as babies. The baby pictures did not identify the celebrities. readers were asked to match each celebrity with the correct baby pictures. What is the probability that a reader guessing at random will match all three correctly? 19

Answers

The readers will most likely match the pictures by looking at the eye differences and facial differences.
I believe 1/3, but only use that answer if you dont get any better ones because I am not completely sure.

the base of a regular pyramid is a hexagon whose perimeter is 84 feet. the volume of the pyramid is approximately 4,677.85 cubic feet. find the height of the pyramid.

Answers

Answer:

The height of the pyramid is 27.56\ ft

Step-by-step explanation:

we know that

The volume of the pyramid is equal to

V=(1)/(3)BH

where

B is the area of the base of the pyramid

H is the height of the pyramid

step 1

Find the area B of the regular hexagonal base

we know that

The perimeter of a regular hexagon is

P=6b

where

b is the length side of the hexagon

we have

P=84\ ft

substitute

84=6b

solve for b

b=14\ ft

Remember that the area of a regular hexagon is the same that the area of six equilateral triangles

Determine the area of the six equilateral triangles, applying the formula of the law of sines

B=6[(1)/(2)b^2sin(60\°)]

substitute the value of b

B=6[(1)/(2)(14)^2sin(60\°)]

B=509.22\ ft^2

step 2

Find the height of the pyramid

V=(1)/(3)BH

we have

V=4,677.85\ ft^3

B=509.22\ ft^2

substitute

4,677.85=(1)/(3)(509.22)H

solve for H

14,033.55=(509.22)H

H=14,033.55/(509.22)H

H=27.56\ ft