There are 12.052 ×10²³ atoms in 54 g of aluminium according to the concept of Avogadro's number.
Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number
Substituting the values in the formula,54/26.98×6.022×10²³=12.052×10²³ atoms .
Hence, there are 12.052×10²³ atoms in 54 g of aluminium.
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Answer:
mass Mg = 1.937 Kg
Explanation:
from periodic table for Mg:
⇒ molecular mass Mg = 24.305 g/mol
∴ mol ≡ 6.022 E23 atoms
⇒ mol Mg = (4.80 E25 atoms)×(mol/6.022 E23 atoms)
⇒ mol Mg = 79.708 mol
⇒ mass Mg = (79.708 mol)×(24.305 g/mol)
⇒ mass Mg = 1937.3 g
⇒ mass Mg = 1.937 Kg