reactivity increases
atomic radius increases
atomic mass increases
valence electrons decrease
b. erosion.
c. physical weathering.
d. rock weathering
The correct answer is A. chemical weathering!
There are two types of mixture depending on the distribution of the components in the mixture. Homogeneous mixtures are mixtures which has uniform properties all throughout the solution while heterogeneous mixtures are the opposite they do not exhibit uniformity in any property. Example for a homogeneous is a salt solution where at any point you get a sample the properties are the same. For the heterogeneous mixture, a mixture of sand and salt where at any sampling point the properties are not the same.
a suspension
the particles are big enough to settle
a colloid
the particles are too small to ever settle
a solution
homogeneous mixture of two or more substances
(1) have combined chemically and retain their different boiling points
(2) have combined chemically and have the same boiling point
(3) have combined physically and retain their different boiling points
(4) have combined physically and have the same boiling point
Both 2-propanol and water can be separated by the process of distillation because the 2-propanol and water have combined physically and retain their different boiling points. Thus, the correct option for this question is C.
Distillation may be defined as a methodology through which components are separated from a mixture. It involves the process by which the components are evaporated and the vapors condensed.
2-propanol is also known as Isopropyl alcohol. The boiling point of this is 82.5°C which is lower than that of water. When both 2-propanol and water are mixed they usually get separated through the physical process known as boiling. Water typically starts boiling at 100°C.
Therefore, the correct option for this question is C.
To learn more about Boiling points, refer to the link:
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Answer:
Mass percent of N2H4 in original gaseous mixture = 31.13 %
Explanation:
Given:
Initial mass of gaseous mixture = 61.00 g
Initial mole of oxygen = 10.0 mol
Moles of oxygen remaining after the reaction = 4.062 mol
Moles of oxygen used = 10.0 - 4.062 = 5.938 mol
Total oxygen used in both the reactions = 10.0 parts
out of 10 parts, 3 part react with N2H4.
Now, consider the reaction of N2H4
3 moles of O2 react with 1 mole of N2H4
1.78 moles of oxygen will react with 1.78/3 = 0.5933 mol of N2H4
Molecular mass of N2H4 = 32 g/mol
Total mass = 61.0 g
The mass percent of N2H4 in the gaseous mixture can be determined through stoichiometric calculations and determining the limiting reactant. The initial and remaining amounts of O2 are used to calculate the reacted amount of O2, which then allows for the calculation of the amount of N2H4. This information is used in the mass percent formula.
The balanced reaction states that for one mole of NH3, one mole of O2 is required, while for one mole of N2H4, 3 moles of O2 are required. Thus, the initial moles of O2 were 10 moles and after reaction 4.062 moles O2 remained. Thus, the reacted amount of O2 is 10 - 4.062 = 5.938 moles. From calculating the limiting reactant and applying stoichiometry, the amount of N2H4 can be determined. We know the molar mass of N2H4 is 32 g/mole. By calculating the molar ratio, we can then calculate the mass percent of N2H4 in the mixture using the formula: (mass of N2H4 / total mass) * 100%.
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