It will take the first horse 2.5 hours to run a mil
It will take the second horse 4 hours to run a mil
Find the required graph attached.
The formula for calculating speed is expressed as:
Get the speed of each horse
Speed for the first horse = 5/2 = 2.5 miles/hr
Time = 2.5 * 1
Time = 2.5 hours
Hence it will take the first horse 2.5 hours to run a mile
Speed for the second horse = 4/1 = 4 miles/hr
Time = 4 * 1
Time = 4 hours
Hence it will take the second horse 4 hours to run a mile
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Answer:
Option B
Option C
Step-by-step explanation:
⇒ , which is a real number.
Similarly,
And we also know that
So, we see that odd powers of is a complex number and even powers renders us a real number.
Using this we solve the problem.
Option A: 11 is an odd power. This would be a complex number and not a real number.
Option B: Even power of i. So, this should give us a real number.
Option C:
(a + bi)² = a² - b² + 2abi
So, (2 + 3i)² would be a complex number because of the 2bi term.
Option D: (4 + 5i)(4 - 5i)
(a + ib)(a - ib) = a² + b²
So, (4 + 5i)(4 - 5i) = 4² + 5² = 41, a real number.
Option E: (6 + 8i)(8 + 6i)
(a + ib)(c + id) = ac - bd + (ad + bc)i
This would be a complex number because of the (ad + bc) term.
So, Options B and D are real numbers.
The two numbers in question obtained by creating a system of equations are 56 and 36
Let the two numbers be : a and b
From (2):
Substitute (3) into (1)
a + b = 92
20 + b + b = 92
20 + 2b = 92
2b = 92 - 20
2b = 72
b = 72/2
b = 36
From (3) :
a = 20 + 36
a = 56
Therefore, the two numbers are 56 and 36
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B. (9x^2 + 1)(9x^2 – 1)
C. (3x^2 + 1)^3(3x – 1)
D. (9x^2 + 1)(3x + 1)(3x – 1)
Using this: a²-b²=(a+b)(a-b)
81x^4-1=
(9x²)²-1=
(9x²-1)(9x²+1)= (in the bold half we use the formula again)
(3x+1)(3x-1)(9x²+1)
So the answer is D