Taking into account the definition of dilution, the molarity of the diluted solution is 0.125 M.
When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.
Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
In this case, you know:
Replacing in the definition of dilution:
0.15 M× 125 mL= Cf× 150 mL
Solving:
(0.15 M× 125 mL)÷ 150 mL= Cf
0.125 M= Cf
In summary, the molarity of the diluted solution is 0.125 M.
Learn more about dilution:
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Answer:
0.125 M
Explanation:
M₁V₁ = M₂V₂
125 mL / 1000 = 0.125 L = V₁
25 + 125 = 150 mL / 1000 = 0.150 L = V₂
0.15 M = M₁
M₁ × V₁ / V₂ = M₂
(0.15) × (0.125) / (0.150) = 0.125 M
0.125 M is the answer
Explanation:
Substances with their density less than the density of water which is 1 g/cm³ will float on it whiles those greater than that of water will sink into the water.
From the question the density of the object is 0.8 g/cm³
Since it's density is less than that of water the object will float on water .
Hope this helps you
An object with a density of 0.8 g/cm3 will float in water because its density is less than the density of water, which is 1 g/cm3.
The question is asking whether an object with a density of 0.8 g/cm3 will float or sink in water. Floating and sinking are determined by the principle of buoyancy, which depends on the density of the object compared to the fluid (in this case, water) it is placed in.
Water has a density of 1 g/cm3. So, if the object's density is less than 1 g/cm3, it will float, if it's more it will sink. Since 0.8 g/cm3 is less than 1 g/cm3, an object with this density will float in water.
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B. n=1 to n=6
C. n=1 to n=5
D. n=5 to n=1
Answer:
Explanation:
Niels Bohr was a Danish physicist who proposed the hydrogen atom quantum model to explain the discontinuity of the atom's emission spectra.
In Bohr hydrogen atom model, the electrons occupy orbits identified with the numbers n = 1, 2, 3, 4, ... Each number (orbit) corresponds to a different energy level or state. The number n = 1 corresponds to the lowest energy level, and each higher number corresponds to a higher energy level.
This table shows the relative energy of the different orbits of the Bhor hydrogen atom:
Orbit Quantum Energy Relative
number level energy
First n = 1 1 E₁
Second n = 2 2 2E₁
Third n = 3 3 9E₁
Fourth n = 4 4 16E₁
Fifth n = 5 5 25E₁
Sixth n = 6 6 36E₁
Seventh n = 7 7 49E₁
When an electron jumps from a higher energy state down to a lower energy state, it emits a photon with an energy equal to the difference of the energies between the initial and the final states.
Since the n = 6 to n = 1 transition results in the higher relative energy difference (36E₁ - E₁ = 35E₁), you conclude that it is this transition which results in the emission of the highest-energy photon, which is the option A.
In the Bohrhydrogen atom model, the highest energy photon is emitted during the transition from the highest energy level to the lowest energy level. For the given options, the highest energy photon would be emitted in the transition from n=6 to n=1.
In the Bohr hydrogen atom model, the highest energyphoton is emitted during the transition from the highest energy level to the lowest energy level. In our choices, the largest transition (indicating the greatest energy change) is from n=6 to n=1. This is because the energy difference between the energy levels is the greatest, resulting in the emission of a photon with the highest energy.
In general, the greater the transition between the energy levels in a hydrogen atom (i.e. the more levels the electron 'jumps' downward), the higher the energy of the emitted photon.
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b. decreases.
c. remains the same.
d. cannot be predicted.