How many rectangles can you build with a prime number of square tiles?

Answers

Answer 1

Answer: You can only make 1 rectangle because 2 square tiles would make a rectangle and 2 is the only prime number that could be used to make a rectangle if the prime number is the amount of tiles used.

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F(x)= -4x²-7 find, Help Please!!a.f(x)-f(a)/x-a =

b. f(x-h)-f(x)/h =

Answers

Answer:

Step-by-step explanation:

a. (-4x^2-7) - (-4a^2-7) / x-a

b. (-4(x-h)^2-7) - (-4x^2-7) / h

since there are no numbers to plug in for the variables (a, h, x) there is no possible numerical value for the equations. The format of the equations seems familiar in the sense of limits for calculus, but I could be wrong.

I did too know 5678 and 9

Answers

ok so
quadrilateral-4 sides
1. not a paralellogram
A. trapezoid (1 pair of paralell sides)
2. paralellogram (2 pairs of paralell sides)
A. rectangle-4 right angles
B. rhombus-4 equal sides
C. squaer - 4 equal sides and 4 right angles (both a rhombus and rectangle)
D. kite. 2 pairs of paralell sides that are next to each other (looks like a kite)

5. 4 equal sides, no right angle: rhombus
6. 4 right angles, all sides equal legnth:squaer
7. 1 pair of paralel sides:trapezoid
8. 4 right angles:rectangle
9. if a rectangle has 4 equal sides it is technically a squaer and a rhombus
all squares are recangles and rhombuses, but not all rhombuses and rectangles are squaers

5. rhombus
6. square
7. trapezoid
8. rectangle
9. it is has 4 equal sides, then yes

What is the solution to the equation 4 + 3sqrt 2y = 6

Answers

Answer:

the answer it's not correct because you have to put the 6x

Step-by-step explanation:

if you do not put an x after you put the number it would you would get it wrong

2loga(3)+loga(5)=loga(x)

Answers

$2log_a(3)+log_a(5)=log_a(x)\ \ \ \ a>0\ \ and\ \ a \neq 1\ \ \ \ \ \ \ D=(0;+\infty) \n\nlog_a(3^2)+log_a(5)=log_a(x)\n\nlog_a(9\cdot5)=log_ax\ \ \ \Leftrightarrow\ \ \ x=45\ \ \in\ D\n\nAns.\ x=45$

Y=x^3+125

Needs to be factored

Answers

$a^3+b^3=(a+b)(a^2-ab+b^2)\n\n\ny=x^3+125=x^3+5^3=(x+5)(x^2-5x+5^2)\n\n=(x+5)(x^2-5x+25)$

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the weights in pounds of 1111 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that sport's league? 186 229 240 257 187 221 309 293 257 274 221

Answers

Answer:

(a) Mean =243.0909

(b) Median = 240

In other words it is the middle value of the data arranged in order.

(d) Mid Range = 247.5

Variance = 1578.5037

Standard Deviation = 39.730

Range = 309-186= 123

(e) No the results are not likely to be representative of all players in that sport's league because they are not similar.

Step-by-step explanation:

First arranging the data in ascending order

186 187 221 221 229 240 257 257 274 293 309

(a) Mean = Sum of observations/ No of observations

= 186 + 187 + 221 +221 + 229 + 240 + 257 + 257 + 274 + 293 + 309 /11

= 2674/11=

= 243.0909

(b) Median for un grouped data is

Here n = 11 and n/2 = 11/2 is not an integer

Median = Results obtained by ([n/2] +1) player

= (11/2 +1) = 6th player in ordered data

= 240

In other words it is the middle value of the data arranged in order.

(c) Mode = Most frequent values.

There are two modes : 221 and 257 . These both values occur repeatedly.

(d) Mid Range = Maximum Value + minimum value/ 2= 186+ 309/2= 247.5

Now we will find the variance and standard deviation

The variance is given by

s² = (186-243.0909)²+ (187-243.0909)²+ (221-243.0909)²+ (221 -243.0909)²+(229-243.0909)²+ (240-243.0909)²+( 257-243.0909)²+ (257 -243.0909)²+ (274-243.0909)²+ ( 293-243.0909)²+ (309 -243.0909)²/11-1

s²= 3259.370 + 3146.139+ 488.008+ 488.008+ 198.553+ 9.554+ 193.463 + 193.463 + 955.372 + 2509.098 + 4344.009/10

s²= 15,785.037/10= 1578.5037

And Standard Deviation = s= √1578.5037= 39.730

Variance = 1578.5037

Standard Deviation = 39.730

Range = 309-186= 123

(e) No the results are not likely to be representative of all players in that sport's league because they are not similar.

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