Anthony walks to the pizza place for lunch. he walk 1 km east, then 1 km south and then 1 km east again. what distance did he cover? what was his displacement?

Answers

Answer 1

Answer: he covered an amount of 2 km to east and one to south. the displacement, yeah i dont have that sorry :[

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1. The photon energy for light of wavelength 500 nm is approximately (Show your work).1.77 eV 3.10 eV 6.20 eV 2.48 eV 5.46 eV 2. Which of the following colors is associated with the lowest temperature? Explain your reasoning. A. Blue B. Green C. Yellow D. Red 3. Which of the following colors has the highest photon energy? A. Blue B. Green C. Yellow D. Red Explain your reasoning.

fastest humans can reach speeds of about 11 m/s. part a in order to increase his gravitational potential energy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb? express your answer to two significant figures and include the appropriate units.

Answers

Answer:

6.17 m

Explanation:

speed, v = 11 m/s

Let the mas is m.

As according to the question

Potential energy = kinetic energy

m x g x h = 0.5 m v²

where, h is the height raised.

9.8 x h = 0.5 x 11 x 11

h = 6.17 m

Thus, the height raised is 6.17 m .

An Olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds. What is the average acceleration of the sprinter?

Answers

The sprinter accelerates at 1.1 meter per second.

Tunicates resemble a _____ on the sea floor. rod square sac hole

Answers

Answer: sac

Tunicates are sea squirts that are found in the marine water. These animals remains attached to the rocks and the sea beds. They exhibit a body shape which looks like a barrel. The barrel has two openings called as siphons. These siphon helps in the intake of the food particles and oxygen. These animals look like sac on the sea floor.

Which of the following condition would decrease the ability of a person to hear a sound?

Answers

These are some conditions that can possibly decrease the ability of person to hear a sound:
1. Blockage of the ear canal - ear wax is naturally produced by our ear canal which serves as self- protection. It also block sounds if the ear canal is not well cleaned.
2. Foreign bodies in the ear canal - foreign bodies such as beads, left residue of cotton, peas or even small insects like bugs, bees, and spiders.
3. Infected Eardrum - eardrum catches sound waves that passes through the ear canal. If the eardrum is damage, it may lessen its ability to catch sound effectively.

An engine raises 100kg of water through a height of 60m in 20s. what is the power of the engine

Answers

Answer:

the answer is 3000

Explanation:

power=mass×gravity×height or (divided by /Time)

so 100kg×10×60m/20s

=60,000/20

=3000joule

if I am wrong correct me

The vapor pressure of ethanol is 1.00 × 102 mmHg at 34.90°C. What is its vapor pressure at 60.61°C? (ΔHvap for ethanol is 39.3 kJ/mol.) mmHg

Answers

Answer:

The vapor pressure of ethanol at 60.61 °C is 327.56 mmHg

Explanation:

using Clausius-Clapeyron equation

$ln((P_2)/(P_1)) = (\delta H)/(R)((1)/(T_1) -(1)/(T_2))$

where;

ΔH is the enthalpy of vaporization of ethanol = 39.3 kJ/mol

R is ideal gas constant = 8.314 J/mol.K

P₁ is the initial pressure of ethanol at T₁ = 1.00 × 10² mmHg

P₂ is the final pressure of ethanol at T₂ = ?

T₁ is the initial temperature = 34.9°C = 307.9 K

T₂ is the final temperature = 60.61°C = 333.61 K

$ln((P_2)/(P_1)) = (\delta H)/(R)((1)/(T_1) -(1)/(T_2)) \n\nln((P_2)/(100)) = (39300)/(8.314)((1)/(307.9) -(1)/(333.61))\n\nln((P_2)/(100)) = 4726.9666 (0.003248 -0.002997)\n\nln((P_2)/(100)) = 4726.9666 (0.000251) = 1.1865\n\n((P_2)/(100)) = e^((1.1865)) \n\n((P_2)/(100)) = 3.2756\n\nP_2 = (100*3.2756)mmHg\n\nP_2 = 327.56 mmHg$

Therefore, the vapor pressure of ethanol at 60.61 °C is 327.56 mmHg

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